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Molodets [167]
3 years ago
14

Energy may be measured in?​

Physics
1 answer:
hram777 [196]3 years ago
6 0

Answer:

Energy May be measured in joule

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Halogen is most likely to react to what
arsen [322]
Halogens therefore react most vigorously with Group 1 and Group 2 metals of all main group elements.
4 0
3 years ago
A jet travels 1000 kilometers in 5 hours. What is its average speed?
nlexa [21]

Given:

Total distance = 1000 kilometer

Total time = 5 hours

To find:

Average speed = ?

Formula used:

v_{avg} = \frac{s}{t}

Where v_{avg} = average speed

s = total distance

t = total time

Solution:

Average speed of the jet is given by,

v_{avg} = \frac{s}{t}

Where v_{avg} = average speed

s = total distance

t = total time

v_{avg} = \frac{1000}{5}

v_{avg} = 200 km/ h

Thus, average speed of the jet is 200 km/h.

Hence, Option (A) is correct.


7 0
3 years ago
What information and measurements would you need to calculate the rate of movement?
aliina [53]
When you talk about rate, you will expect that it will be in terms of a time unit. It measures how fast it is going. So, you would expect that the denominator is in time units. For the movement, you can measure this with either distance or velocity.

So, for the first variety, you would need distance and time to measure the rate of how far you go at a certain time. It is also called as velocity. For the second variety, you would need velocity and time to measure the rate of how fast you are going at a certain interval. It is also called as acceleration.
8 0
3 years ago
Compared to a plane gravitational pull on the ground to 7 miles in sky is what
Citrus2011 [14]
When you're in an airplane that's 7 miles up off the ground, the strength of gravity plunges to only 99.6 percent of its strength all the way down on the ground. A big heavy person, who weighs 200 pounds down at the airport, weighs only 199 pounds 4.7 ounces in a plane at the altitude of 7 miles.
4 0
3 years ago
Two subway stops are separated by 1210 m. If a subway train accelerates at 1.30 m/s2 from rest through the first half of the dis
solong [7]

Answer:

Part 1) Time of travel equals 61 seconds

Part 2) Maximum speed equals 39.66 m/s.

Explanation:

The final speed of the train when it completes half of it's journey is given by third equation of kinematics as

v^{2}=u^2+2as

where

'v' is the final speed

'u' is initial speed

'a' is acceleration of the body

's' is the distance covered

Applying the given values we get

v^2=0+2\times 1.30\times \frac{1210}{2}\\\\v^{2}=1573\\\\\therefore v=39.66m/s

Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as

v=u+at\\\\v=0+1.30\times t\\\\\therefore t=\frac{39.66}{1.30}=30.51seconds

Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance

Thus total time of journey equalsT=2\times 30.51\approx61seconds

Part b)

the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals 39.66m/s

4 0
4 years ago
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