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Nady [450]
3 years ago
14

How can we make use of acids or bases to Prevent the growth of microorganisms in swimming pools?

Chemistry
1 answer:
pentagon [3]3 years ago
8 0
By putting smarticle particles 
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WILL GIVE BRAINIEST IF HELP Which of these is a compound
NikAS [45]

b the awnser is b its a compound of carbon C and 2 oxygon atoms O sub 2

5 0
3 years ago
An unknown compound has the following chemical formula:
Softa [21]

Answer:

Formula of the compound = P_2O_5

Explanation:

Given,

No. of mole of O = 8.20 mol

No. of mole of P = 3.30 mol

Chemical formula = P_2O_x

Ratio of P and O = \frac{2}{x}

\frac{2}{x} =\frac{3.3}{8.20} \\x \times 3.3 = 8.20 \times 2\\x = \frac{8.20 \times 2}{3.3} \\x=4.9969\\ = 5

formula of the compound = P_2O_5

5 0
3 years ago
The expression below was formed by combining different gas laws. V is proportional to StartFraction n T over P EndFraction. Whic
Ronch [10]

Answer:

The Ideal gas law

Explanation:

From the given question, we have:

V \alpha \frac{nT}{P}

where each variable has its usual meaning.

Thus,

V = \frac{nRT}{P}

where R is the ideal gas constant

cross multiply to have;

PV = nRT

This implies that the volume of the gas is directly proportional to the number of moles of the gas.

Therefore, the law can be used to determine the relationship between the volume and number of moles is the ideal gas law.

3 0
2 years ago
Can you please help me and can you show your work please
natali 33 [55]

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

1.2mol*\frac{40.00g}{1mol} =41.2g

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

45g*\frac{1mol}{180.15g}=0.25g

4. Here, since the molar mass of ammonia is 17.03 g/mol:

20mol*\frac{17.03g}{1mol}=340.6g

5. Here, since the molar mass of SO2 is 64.06 g/mol:

48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules

Best regards!

5 0
3 years ago
The levels of organization within an organism are atom,
OleMash [197]

Answer:

The answer is: Molecule and Organ system.

4 0
1 year ago
Read 2 more answers
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