If the temperature of the sample of gas increases to the given value, the volume also increases to 600mL.
<h3>What is Charles's law?</h3>
Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.
It is expressed as;
V₁/T₁ = V₂/T₂
Given the data in the question;
- Initial temperature of gas T₁ = 100K
- Initial volume of gas V₁ = 300mL
- Final temperature T₂ = 200K
V₁/T₁ = V₂/T₂
V₂ = V₁T₂ / T₁
V₂ = ( 300mL × 200K ) / 100K
V₂ = 60000mLK / 100K
V₂ = 600mL
Therefore, if the temperature of the sample of gas increases to the given value, the volume also increases to 600mL.
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Answer:
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you may think that if it has a + it would be bigger, but it is actually the opposite.
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Answer:
Molality of the solution = 0.7294 M
Explanation:
Given:
Number of magnesium arsenate = 1.24 moles
Mass of solution = 1.74 kg
Find:
Molality of the solution
Computation:
Molality of the solution = Mole of solute / Mass of solution = 1.74 kg
Molality of the solution = 1.24 / 1.7
Molality of the solution = 0.7294 M
Answer:
answer is option 2 hope it helps