Answer:
Molarity = 1.0 M
Explanation:
<u>Step 1: </u>Data given
Mass of H3BO3 = 61.8 grams
Mass of water = 1,000 grams = 1kg
Molality = 1.0 molal
<u>Step 2:</u> Calculate number of moles
1.0 molal = 1 mol of solute/ 1kg of solvent
Number of moles = molality * mass of the solvent = 1.0 mol/kg * 1kg = 1 mol
This means 61.8 grams of H3BO3 should be 1 mol
We can control this:
Number of moles = mass / molar mass
Number of moles H3BO3 = 61.8/ 61.83 g/mol = 1 mol
<u>Step 3</u>: Calculate the volume of water
Let's suppose the density of water is 1g/mL
Volume of water = mass / density
Volume = 1,000 grams / 1g/mL
Volume = 1,000 mL = 1.00 L
<u>Step 4: </u>Calculate molarity
Molarity = number of moles / volume
Molarity = 1 mol / 1.00 L
Molarity = 1.0 M
For dilute AQUEOUS solutions molality ≅ molarity