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ycow [4]
3 years ago
12

Which substance is used to remove rust from metal

Chemistry
2 answers:
Anvisha [2.4K]3 years ago
7 0
<span>hydrochloric acid (HCl)</span>
wel3 years ago
3 0
<span>Chemically speaking, rust is a base and any acid will remove it. The choice of acid is going to be the thing to consider, since acid + base = salt and water. Phosphoric acid left a residue because the salt Iron phosphate is insoluble in water. Iron's soluble salts include the chloride, the sulfate and the nitrate. Industrially speaking, you need to "pickle" your iron. Pickling is a process in which dilute sulfuric acid is used to remove any surface corrosion prior to either painting or plating an iron surface. Sulfuric acid is ordinary battery acid and the salt Iron sulfate is not toxic. Sulfuric acid is one of the most common acids used (besides hydrochloric acid). The dilute kind is not terribly corrosive but concentrated sulfuric acid is a thick, syrupy liquid which can cause some nasty chemical burns if allowed to remain on the skin. It also heats up quite a lot when water is added, so this is an "Acid to water not water to acid" situation. The other choice is Hydrochloric acid, known as muriatic acid. The 20% concentrate is available in nearly any hardware store. It isn't as corrosive as concentrated sulfuric acid, but it has a burning, acrid stench, so never use the concentrate without adequate ventilation. It is ordinarily used to remove hard water deposits (boiler scale) but does a good on on rust as well. Concentrated Iron chloride isn't entirely inert but lots of rinsing will turn it back into harmless rust/sludge, especially if the rince water is naturally hard. Nitric acid will remove corrosion from anything, but it is extremely corrosive, smells worse then Hydrochloric acid and isn't easy to get, since it can be used to create some powerful explosives</span>
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Oxygen and hydrogen are kept under the same temperature and pressure. Oxygen molecule is 16 times more massive than hydrogen one
lozanna [386]

Explanation:

When we increase the temperature of a substance then there will occur an increase in the kinetic energy of its molecules.

Also,      K.E = \frac{3}{2}kT

So, kinetic energy is directly proportional to the temperature.

Hence, when temperature and pressure are kept the same for both oxygen and hydrogen gas then values of their kinetic energy will be the same irrespective of their masses.

Thus, we can conclude that kinetic energy of oxygen molecule is the same as compared to hydrogen molecule.

3 0
3 years ago
If you have studied the chemistry of fats can you identify the end arrangement found in fatty acids as well as amino acids? What
White raven [17]
Answers:
1) - COOH
2) carboxyl group

The organic acids contain the carboxyl group: - COOH.

Fats are structures composed by fatty acids. Fatty acids are long aliphatic chains with a carboxyl group at the end.

Aminoacids are chains that contains amine group (NH2) at one end and the carboxyl group at the other end.

Then both aminoacids and fatty acids contain the carboxyl group (-COOH) at one end.
8 0
3 years ago
If you are given an unknown liquid that is 1.0 L and has the mass of 500 grams which of the substance would it be. Distilled Wat
kodGreya [7K]
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8 0
3 years ago
Ideal He gas expanded at constant pressure of 3 atm until its volume was increased from 9 liters to 15 liters. During this proce
kkurt [141]

Explanation:

The given data is as follows.

             P = 3 atm

                = 3 atm \times \frac{1.01325 \times 10^{5} Pa}{1 atm}  

                 = 3.03975 \times 10^{5} Pa

    V_{1} = 9 L = 9 \times 10^{-3} m^{3}    (as 1 L = 0.001 m^{3}),  

        V_{2} = 15 L = 15 \times 10^{-3} m^{3}

            Heat energy = 800 J

As relation between work, pressure and change in volume is as follows.

                  W = P \times \Delta V

or,                W = P \times (V_{2} - V_{1})

Therefore, putting the given values into the above formula as follows.

                  W = P \times (V_{2} - V_{1})

                      = 3.03975 \times 10^{5} Pa \times (15 \times 10^{-3} m^{3} - 9 \times 10^{-3} m^{3})

                      = 1823.85 Nm

or,                   = 1823.85 J

As internal energy of the gas \Delta E is as follows.

                     \Delta E = Q - W

                                  = 800 J - 1823.85 J

                                  = -1023.85 J

Thus, we can conclude that the internal energy change of the given gas is -1023.85 J.

8 0
3 years ago
Explain what would happen to the air temperature at Riverdale School over the course of the
Ira Lisetskai [31]

Answer:

In each Amplify Science unit, students figure out

a phenomenon by asking questions, gathering

evidence, and coming up with an explanation of how

the phenomenon works. The Coherence Flowchart

visually represents the storyline of the unit, showing

the coherent flow of questions, evidence, and ideas that

support students as they build complex explanations

of the unit’s anchor phenomenon. The Coherence

Flowchart on the following pages (one chapter per

page) can be used to see the connections between

the questions that drive students’ experiences, the

evidence they gather, the ideas they figure out, and the

new questions that those ideas generate. The diagram

to the right explains the structure of a chapter in the

Explanation:

7 0
3 years ago
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