Answer:
y intercept - (0, 275)
x intercept - (0, 125)
Step-by-step explanation:
Given the graph y = f(x)
The graph y = f(cx), where c is a constant is refered to as horizontal stretch/compression
A horizontal stretching is the stretching of the graph away from the y-axis.
A horizontal compression is the squeezing of the graph towards the
y-axis. A compression is a stretch by a factor less than 1.
If | c | < 1 (a fraction between 0 and 1), then the graph is stretched horizontally by a factor of c units.
If | c | > 1, then the graph is compressed horizontally by a factor of c units.
For values of c that are negative, then the horizontal
compression or horizontal stretching of the graph is followed by a
reflection across the y-axis.
The graph y = cf(x), where c is a constant is referred to as a
vertical stretching/compression.
A vertical streching is the stretching of the graph away from the x-axis. A vertical compression is the squeezing of the graph towards the x-axis. A compression is a stretch by a factor less than 1.
If | c | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of c units.
If | c | > 1, then the graph is stretched vertically by a factor of c units.
For values of c that are negative, then the vertical compression or vertical stretching of the graph is followed by a reflection across the x-axis.
By letting

we get derivatives


a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

Examine the lowest degree term
, which gives rise to the indicial equation,

with roots at r = 0 and r = 4/5.
b) The recurrence for the coefficients
is

so that with r = 4/5, the coefficients are governed by

c) Starting with
, we find


so that the first three terms of the solution are

Answer:
2x+3y+5
Step-by-step explanation:
Firstly, we remove the parenthesis since there is nothing in front of it.
There is a “+” sign in front of the parenthesis, it stays the same.
Secondly, we combine like terms. We combine the x’s, the y’s, and the normal numbers without a variable.
Finally, after combining the like terms. You end up with “2x+3y+5”.
Here you're being asked to find the "perimeter" of the space, even tho' the problem doesn't specifically ask for it.
The formula for P is P = 2W + 2L.
Here the width, W, is 3 1/2 yds, and the length, L, is 4 2/3 yds. Subbing these two values into the formula for P (above) results in:
P = 2(3 1/2 yds) + 2(4 2/3 yds)
= 7 yds + 9 1/3 yds = 16 1/3 yds, total.