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ASHA 777 [7]
3 years ago
12

Which is equivalent to 3/8"? o o o o

Mathematics
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

decimal form would be 0.375

these are all also equivalent 6/16 9/24 12/32 15/40 18/48 21/56 24/64 27/72 30/80 33/88 36/96 .375

i would just pick the one you have the options with since you just asked a question with no choices but i hope this helps

Step-by-step explanation:

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Ian is a phycologist interested in determining the proportion of algae samples from a local rivulet that belonged to a particula
pickupchik [31]

Answer: 16590

Step-by-step explanation:

The formula we use to find the sample size is given by :-

, where p = prior estimate of population proportion.

z^*= Critical z-value (Two- tailed)

E= Margin of error .

Let p be the population proportion of cyanobacteria.

Given : E = 0.01

Critical value for 99% confidence interval : z^*=2.576

If Ian does not want to rely on previous knowledge , then we assume p=0.5 because the largest standard error is at p=0.5.

Now, the required sample size = n=0.5(1-0.5)(\frac{2.576}{0.01})^2

n=0.25(257.6)^2=0.25(66357.76)=16589.44\approx16590

Required sample size = 16590

5 0
2 years ago
Which expressions are equivalent to - 62+(-5.5) + 1.5z + 7y-3.5?
baherus [9]
I believe that the correct answer is C
8 0
2 years ago
PLEASE HELP!!! I need the answer and the work to go along with it.
Masja [62]
----------------------------------------------------------------------------------------------------
Check the picture attached.

the secants of the circle, BA and DC, intersect at point P, as shown.

i)
let m(P)=a

ii)
let m(CDA)=b, then the measure of ar CA is 2b, as "the measure of an inscribed angle is half the measure of the arc it intercepts"

iii)
m(DAB)= m(P)+m(CDA)= a+b, as DAB is an exterior angle of the triangle PAD.

iv)
then the measure of arc DB is 2m(DAB)=2(a+b)=2a+2b

v)
m(P)= \frac{(2a+2b)-2b}{2}= \frac{m(DB)-m(CA)}{2}

This is always true,
----------------------------------------------------------------------------------------------------

In our problem, there is a slight difference, we have 1 secant and one tangent, but it is just a special case and nothing changes.

As an exercise, we can repeat the steps of the general proof, by first joining U and T.
----------------------------------------------------------------------------------------------------

by the theorem we just proved,

m(R)=(m(TU)-m(SU))/2

30°=(100°-m(SU))/2

60°=100°-m(SU)

m(SU)=40°

5 0
2 years ago
Confused on this so please help:
scoray [572]

The equation p=4+3y is maximised at (4,5) and the maximised value is 31.

Given equation p=4x+3y and constraints x>0,x<4, y<5.

We have to maximise the equation p=4x+3y with constraints x>0,x<4,y<5.

To find out the points we have to make graphs of the constraints first.

From the graph we have found that points are (0,0),(0,5),(4,0),(4,5).

The above points are common points of graphs of all constraints.

The value of equations are as under:

At (0,0) , p=4*0+3*0=0

At (0,5), p=4*0+3*5=15

At (4,0),p=4*4+3*0=16

At (4,5),p=4*4+3*5=16+15=31

Maximum value of p is 31 and that is for (4,5).

Hence the equation is maximised at (4,5) and the maximum value is 31.

Learn more about equation at brainly.com/question/2972832

#SPJ4

4 0
1 year ago
Can someone help me with my extra credit? It would be greatly appreciated.
topjm [15]

Answer: I think the answer you need is g. tell me if its wrong though.

4 0
3 years ago
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