What became of alchemy after the 1700s
1 answer:
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Answer:
0.03g/mL
Explanation:
Given parameters include:
Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL
Dilution factor = 10-to-1
The absorbance at 595 nm was 0.78
Mass of the diluted sample = 0.015 mg
We need to first determine the concentration of the diluted sample which is required in calculating the protein concentration of the original solution.
So, to determine the concentration of the diluted sample, we have:
concentration of diluted sample =
= (where ∝ was use in place of μ in the expressed fraction)
= 0.003 mg/μL
The dilution of the sample is from 10-to-1 indicating that the original concentration is ten times higher; as such the protein concentration of the original solution can be calculated as:
protein concentration of the original solution = 10 × concentration of the diluted sample.
= 10 × 0.003 mg/μL
= 0.03 mg/μL
= 0.03g/mL
Hence, the protein concentration of the original solution is known to be 0.03g/mL
Hello!
To find the mass in grams of 2.00 * 10²³ molecules of F₂ you'll need to apply the Avogadro's number, which tells the number of molecules in a mol of a substance, and the Molar Mass, which tells the weight of a mole of a substance. These two quantities are used in the following conversion factor:
So, the mass of 2.00 * 10²³ molecules of F₂ is 12,51 g
Have a nice day!
To find the mass in grams of 2.00 * 10²³ molecules of F₂ you'll need to apply the Avogadro's number, which tells the number of molecules in a mol of a substance, and the Molar Mass, which tells the weight of a mole of a substance. These two quantities are used in the following conversion factor:
So, the mass of 2.00 * 10²³ molecules of F₂ is 12,51 g
Have a nice day!