1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stellarik [79]
2 years ago
5

Suppose that a sample of gas occupies 187 mL

Chemistry
1 answer:
drek231 [11]2 years ago
7 0

Answer:

V2 = 90.7 mL

Explanation:

pressure and volume are inversely proportional, if the pressure is increased, the volume will decrease. In an isothermal process:

p1V1 = p2V2

V2 = p1V1/p2 = (277 torr×187 mL)/571 torr

V2 = 90.7 mL

You might be interested in
Green (Gg) Is crossed with a yellow pea plant (Gg )
Kobotan [32]
GG | Gg
-----------
Gg | gg
5 0
2 years ago
Read 2 more answers
29. All synthetic elements are...
lara31 [8.8K]

Answer:

D

Explanation:

pretty sure it is D. useful in making plastics

6 0
2 years ago
The principal component of mothballs is naphthalene, a compound with a molecular mass of about 130 amu, containing only carbon a
DIA [1.3K]

Answer:

Empirical formula = C5H4

Molecular formula = C10H8

Explanation:

When the 3000 mg of naphthalene are burned they produce 10.3 mg of CO2. Knowing the unbalanced equation of the combustion of naphthalene, we have:

CxHy + O2 = CO2 + H2O

We calculate the molar composition of the sample. We look for the molecular weights in the periodic table:

CO2 = 12,011 + 2 (15,999) = 44,009 g

Mol C = 10.3 mg * (1 mol CO2 / 44.009 g CO2) * (1 mol C / 1 mol CO2) = 0.234 mmol C

Mass C = 0.234 mmol C * (12.011 g C / 1 mol C) = 2.8105 mg C

Mass H = 3 mg - 2.8105 mg = 0.1895 mg H

Mol H = 0.1895 mg H * (1 mol H / 1,008 g H) = 0.188 mmol H

To calculate the empirical formula, we must divide the number of moles of each element by the smallest number of moles, in this case, of hydrogen:

C = 0.2340 mmol C / 0.1895 mol H = 1.25

H = 0.1895 mmol H / 0.1895 mmol H = 1

We multiply the coefficients by 4, and we have the empirical formula:

C1.25 * 4H1 * 4 = C5H4

The molecular formula is equal to (C5H4)m, where m is calculated by the molecular and empirical mass ratio, as follows:

Empirical mass = (5 * 12.011) + (4 * 1.008) = 64.09 g

m = 130 g / 64.09 g = 2.02 = 2

Therefore we have the molecular formula:

(C5H4)2 = C10H8

4 0
3 years ago
What are Rhodium isotopes used for?
Lina20 [59]

Answer:

Rhodium is used to make electrical contacts, as jewelry and in catalytic converters, but is most frequently used as an alloying agent in other materials, such as platinum and palladium. These alloys are used to make such things as furnace coils, electrodes for aircraft spark plugs and laboratory crucibles.

Explanation:

4 0
3 years ago
What is the name of this molecular compound ? F6I5 PLEASE AND THANK YOU
lawyer [7]

Answer:

Hexaflourine Pentaiodide?

Explanation:

f = flourine (6 = hexa)

i = iodine (5 = penta) + ide

5 0
3 years ago
Other questions:
  • What turns blue litmus paper red and have a ph greater than 7?
    9·1 answer
  • Which of the following would be a good use for a nonmetal? A.handle of frying pan
    13·1 answer
  • What salt is produced in hn o 3 (aq) koh(aq)→ h 2 o(l) ?
    11·1 answer
  • An organic chemist measures the temperature T of a solution in a reaction flask. Here is the result. T = 149.206 °C Convert T to
    8·1 answer
  • How many neoutrons does sulenium 82have?
    7·1 answer
  • A.Identify which of the following substances dissolve in water, explaining why for each example: CH4, He, MgSO4, NaHCO3
    9·2 answers
  • Use the drop-down menus to complete the statements about inertia, earth, and the moon.
    14·2 answers
  • Arrange these molecules in order of decreasing mass: C​6​H​14​ , NO​2​ , Fe​2​O​3 ​, and CaCO​
    14·1 answer
  • Which of the following statements best compares the wavelengths of the regions of the electromagnetic spectrum? O Microwaves are
    11·1 answer
  • Questlon 2 of 10
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!