Protons = atomic number = 11
electrons = proton number = 11
neutrons = mass number - atomic number = 23-11 = 12
Answer:
0.8162 gramos de plomo por gramo de yodo
1.633 gramos de plomo por gramo de yodo
Explanation:
Asumiendo una base de 100 gramos para cada compuesto:
Primer compuesto:
Gramos plomo: 44.94g
Gramos de yodo: 100-44.94g = 55.06g
Así, la masa de plomo por gramos de yodo para el primer compuesto es:
44.94g plomo / 55.06g Yodo =
<em>0.8162 gramos de plomo por gramo de yodo</em>
<em></em>
Segundo compuesto:
Gramos plomo: 62.02g
Gramos de yodo: 100-62.02g = 37.98g
La masa de plomo por gramos de yodo para el segundo compuesto es:
62.02g plomo / 37.98g Yodo =
<em>1.633 gramos de plomo por gramo de yodo</em>
Climate is the weather that occur over a long period in a particular place.
Answer:
The value of the Golden Igloo is $227.4 million.
Explanation:
First, we need to find the inner and the outer volume of the half-spherical shell:
The total volume is given by:
Where:
: is the inner volume
: is the inner radius = 1.25/2 = 0.625 m
: is the outer volume
: is the outer radius = 1.45/2 = 0.725 m
Then, the total volume of the Igloo is:
![V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3}](https://tex.z-dn.net/?f=%20V_%7BT%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D%5Cpi%20r_%7Bo%7D%5E%7B3%7D%20-%20%5Cfrac%7B2%7D%7B3%7D%5Cpi%20r_%7Bi%7D%5E%7B3%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D%5Cpi%20%5B%280.725%20m%29%5E%7B3%7D%20-%20%280.625%20m%29%5E%7B3%7D%5D%20%3D%200.29%20m%5E%7B3%7D%20)
Now, by using the density we can find the mass of the Igloo:
Finally, the value (V) of the antiquity is:
Therefore, the value of the Golden Igloo is $227.4 million.
I hope it helps you!
Answer:
C. The lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, all of which have the same spin, in degenerate orbitals.
Explanation:
The Hund's rule is used to place the electrons in the orbitals is it states that:
1. Every orbital in a sublevel is singly occupied before any orbital is doubly occupied;
2. All of the electrons in singly occupied orbitals have the same spin.
So, the electrons first seek to fill the orbitals with the same energy (degenerate orbitals) before paring with electrons in a half-filled orbital. Orbitals doubly occupied have greater energy, so the lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, and for the second statement, they have the same spin.
The other alternatives are correct, but they're not observed by the Hund's rule.
