Answer:
of the stock solution would be required.
Explanation:
Assume that a solution of volume contains a solute with a concentration of . The quantity of that solute in this solution would be:
.
For the solution that needs to be prepared, . The volume of this solution is . Calculate the quantity of the solute (magnesium chloride) in the required solution:
.
Rearrange the equation to find an expression of volume , given the concentration and quantity of the solute:
.
Concentration of the solute in the stock solution: .
Quantity of the solute required: .
Calculate the volume of the stock solution that would contain the required of the magnesium chloride solute:
.
It helps to map out how you will navigate through your unit analysis problem before setting it up.
You are given moles and need grams. What can be used as a conversion factor from moles to grams? Molar mass. We are working with aluminum, so we will need the molar mass of aluminum. My Periodic Table tells me the molar mass of aluminum is approximately 27 g/mol. Now we are ready to set up the unit analysis.
Moles must go on the bottom so that they cancel. Notice how our number of significant figures is 2, so the answer must round to 16 g Al.
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Answer:</h3>
16 grams
Answer:
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Answer:
16mL
Explanation:
Using the following formula;
CaVa = CbVb
Where;
Where
Ca = concentration/molarity of acid (M)
Va = volume of acid (mL)
Cb = concentration/molarity of base (M)
Vb = volume of base (mL)
According to the information provided in this question;
Ca (HCl) = 2M
Cb (NaOH) = 5M
Va (HCl) = 40mL
Vb (NaOH) = ?
Using CaVa = CbVb
Vb = CaVa/Cb
Vb = 2 × 40/5
Vb = 80/5
Vb = 16mL
You need the equation to solve, like the relation between water and carbon dioxide!