The balanced half-cell equation for the reaction occurring at the anode is H2 ---> 2H(+) + 2e(-)
E<u>xplanation:</u>
- The balanced half-cell equation taking place at the anode is explained below
- The product produced in the reaction in the fuel cell is water.
- H2 ---> 2H(+) + 2e(-)
- In the above reaction, the oxidation state of hydrogen switches from 0 to +1.
- It is becoming oxidized by delivering two electrons at the anode.
- In the fuel cell, hydrogen molecules get oxidized to hydronium ions.Thus half-reaction is the oxidation reaction.
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Answer
pH=8.5414
Procedure
The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.
pH = pKa + log₁₀ ([A⁻] / [HA])
Where
pH = acidity of a buffer solution
pKa = negative logarithm of Ka
Ka =acid disassociation constant
[HA]= concentration of an acid
[A⁻]= concentration of conjugate base
First, calculate the pKa
pKa=-log₁₀(Ka)= 8.6383
Then use the equation to get the pH (in this case the acid is HBrO)
A) Temperature does not affect reaction rate
Answer: The electronic configuration of nitrogen is 1s2 2s2 2p3. Thus nitrogen has a half-filled p orbital, which is comparatively more stable. Thus the p orbital is the outermost orbital. To achieve a stable gas configuration, nitrogen needs to have a fulfilled p orbital.
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