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SashulF [63]
3 years ago
15

A 500-n parachutist opens his chute and experiences an air resistance force of 800 n. the net force on the parachutist is then

Physics
2 answers:
Tasya [4]3 years ago
6 0

Force of 500 N is acting on the parachutist.

Parachutist applies 500 N force in downward direction.

Answer:

300 N upward

Solution:

Parachutist feels air resistance of 800 N.

Thus, 800 N of force is acting in upward direction.

Total force acting on the parachutist is given by,

F_{net} = air resistance force - force of parachutist

F_{net} = 800-500

F_{net} = 300 N

Direction of force is in upward direction because the air resistance force is more than force of parachutist.

andriy [413]3 years ago
5 0
The net force of the parachuting guy is 300 N upward.
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A ray of light has a wavelength of
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Answer:

The wavelength in vacuum is equal to 428.8 nm.

Explanation:

Given that,

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n=\dfrac{\lambda_v}{\lambda}\\\\\lambda_v=n\times \lambda\\\\\lambda_v=1.51\times 284\\\\\lambda_v=428.8\ nm

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3 years ago
A parallel plate capacitor is charged up by a battery. The battery is then disconnected, but the charge remains on the plates. T
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Answer:

a. Decreases

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d. Increases

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d is the distance

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V = Ed, since, the electric field remains the

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3 years ago
If the pH of a solution decrease's, is the solution getting more acidic or lees acidic
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The solution becomes more acidic.

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6 0
3 years ago
A 30-g bullet is fired with a horizontal velocity of 450 m/s and becomes embedded in block B, which has a mass of 3 kg. After th
Zolol [24]

Answer:

(a) The velocity of the bullet and B after the first impact is 4.4554 m/s.

(b) The velocity of the carrier is 0.40872 m/s.

Explanation:

(a) To solve the question, we  apply the principle of conservation of linear momentum as follows.

we note that the distance between B and C is 0.5 m

Then we  have

Sum of initial momentum = Sum of final momentum

0.03 kg × 450 m/s = (0.03 kg + 3 kg) × v₂

Therefore v₂ = (13.5 kg·m/s)÷(3.03 kg) = 4.4554 m/s

The velocity of the bullet and B after the first impact = 4.4554 m/s

(b) The velocity of the carrier is given as follows

Therefore from the conservation of linear momentum we also have

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Where:

m₃ = Mass of the carrier = 30 kg

Therefore

(3.03 kg)×(4.4554 m/s) = (3.03 kg+30 kg) × v₃

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The velocity of the carrier = 0.40872 m/s.

3 0
3 years ago
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