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SashulF [63]
3 years ago
15

A 500-n parachutist opens his chute and experiences an air resistance force of 800 n. the net force on the parachutist is then

Physics
2 answers:
Tasya [4]3 years ago
6 0

Force of 500 N is acting on the parachutist.

Parachutist applies 500 N force in downward direction.

Answer:

300 N upward

Solution:

Parachutist feels air resistance of 800 N.

Thus, 800 N of force is acting in upward direction.

Total force acting on the parachutist is given by,

F_{net} = air resistance force - force of parachutist

F_{net} = 800-500

F_{net} = 300 N

Direction of force is in upward direction because the air resistance force is more than force of parachutist.

andriy [413]3 years ago
5 0
The net force of the parachuting guy is 300 N upward.
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           Where L_v is a constant known as heat of vaporization and the value is 2256*10^3J/kg

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                 Q_C = M_s *C_water (100°C)

Where C_{water} is the specific heat of water which has a value 4186J/kg \cdot K

                  Q_C = 0.019 *4186*100 = 7953.4

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