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3 years ago

A 500-n parachutist opens his chute and experiences an air resistance force of 800 n. the net force on the parachutist is then

Physics

2 answers:

Tasya [4]3 years ago

6 0

Force of 500 N is acting on the parachutist.

Parachutist applies 500 N force in downward direction.

Answer:

300 N upward

Solution:

Parachutist feels air resistance of 800 N.

Thus, 800 N of force is acting in upward direction.

Total force acting on the parachutist is given by,

$F_{net}$ = air resistance force - force of parachutist

$F_{net}$ = 800-500

$F_{net}$ = 300 N

Direction of force is in upward direction because the air resistance force is more than force of parachutist.

andriy [413]3 years ago

5 0

The net force of the parachuting guy is 300 N upward.

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2 years ago

Did you think about this over Christmas? I did (-: Before Christmas a 65kg student consumes 2500 Cal each day and stays at the s

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Answer:

a) Em = 332.8 J , b) # jump = 13, c) It is reasonable since there are not too many jumps , d) lower the calories consumed

Explanation:

a) Let's use energy conservation

Initial. On the floor

Em₀ = K = ½ m v²

Final. The highest point

Emf = U = m g h

Energy is conserved

Em₀ = Emf

½ m v² = m g h

h = ½ v² / g

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b) When he was at home he maintained his weight with 2500 cal / day. In his parents' house he consumes 3500 cal / day, the excess of calories is

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They indicate that the body can only use 25% of this energy

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Let's use a Proportion Rule (rule of three), if a jump spends 83.2J how much jump it needs to spend 1046 J

# jump = 1046 J (1 jump / 83.2 J)

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c) It is reasonable since there are not too many jumps

d) That some days consume more vegetables to lower the calories consumed

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