Arboreal
Explanation:
The best term that describes the habitat of bats is arboreal.
The habitat of an organism is its dwelling place in nature. This encompasses the role it plays in the ecosystem.
- Bats spends most of their life time hanging down on trees.
- They are blind flying mammals.
- Animals that lives in trees and trunks are said to be arboreal.
- Other examples are koalas, primates, sloths, spider monkeys, leopards, chameleons etc.
- These animals are adapted for life in tree trunks.
- The have modified body parts that makes them thrive in such habitats.
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In collision type of problems since momentum is always conserved
we can say
So here along with this equation we also required one more equation for the restitution coefficient
so above two equations are required to find the velocity after collision
here the change in velocity occurs due to the contact force while they contact in each other
so this is the impulse of collision while they are in contact with each other while in collision which changes the velocity of two colliding objects
Answer:
It would crack.
Explanation: The pressure from dropping it would crush the eggshell therefore breaking the egg.
Answer:
Explanation:
Work is given by the equation 
where 
is force and 
is displacement.
Displacement is defined as change in position. In this case, the box moves from 5m to 20m. Its displacement is 
.
The force acting on the box is the force of gravity, given as 
.
Therefore, the total work done is:
(two significant figures).
Explanation:
initial height, yo = 2 m
initial velocity, u = 20 m/s
angle of projection,θ = 5 degree
distance of net = 7 m
height of net = 1 m
Let it covers a vertical distance y in time t .
Use Second equation of motion for vertical motion
As it hits the ground in time t, so put y = 0
Taking positive sign, t = 0.84 s
The ball travels a horizontal distance x in time t
X = 20 Cos5 x t
X = 16.76 m
As this distance is more than the distance of net, so it clears the net.
Let t' be the time taken to travel a horizontal distance equal to the distance of net
7 = 20 cos5 x t'
t' = 0.35 s
Let the vertical distance traveled by the ball in time t' is y'.
So,
y' = 2.008 m
So, it clears the net which is 1 m high.
It clears the net by a vertical distance of 2.008 - 1 = 1.008 m and horizontal distance 16.76 - 7 = 9.76 m
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