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Artyom0805 [142]
2 years ago
10

Please Help!!!!

Physics
1 answer:
Len [333]2 years ago
8 0

Answer:

v = 0.92 c

Explanation:

Here, we will use the time dilation formula from Einstein's theory of relativity to find the speed of traveling of the friend:

t =\frac{t_o}{\sqrt{1-\frac{v^2}{c^2}}} \\\\\\\sqrt{1-\frac{v^2}{c^2}}=\frac{t_o}{t}\\\\

where,

v = speed of traveling = ?

c = speed of light

t = time of return = 10 years

t₀ = time passed on earth = 4 years

Therefore,

\sqrt{1-\frac{v^2}{c^2}} = \frac{4\ years}{10\ years}\\\\  1-\frac{v^2}{c^2}=(\frac{2}{5})^2\\\\\frac{v^2}{c^2} = 1-\frac{4}{25}\\\\\frac{v^2}{c^2} = \frac{21}{25}\\\\v^2 = 0.84c^2\\\\

<u>v = 0.92 c</u>

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Answer:Average Velocity of the trip=98.77km/h

Explanation:

Given that:

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Time ran towards east  = 2.3 hours

and then  turned back,

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Let us treat the westward movement as negative movement of the east

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But it seems the value of the distance ran west is wrong , because i do not think he can run  2218km under 1.2hours considering he ran 567.5m due east at 2.3hours .

So Let we use 221.8 km as distance ran due west.

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7 0
3 years ago
A charged particle is moving in a uniform magnetic field at a speed of 8.2Ã10^3 m/s in a direction 87° from the direction of th
77julia77 [94]

Answer:

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Explanation:

It is given that,

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B=\dfrac{0.002}{5.7\times 10^{-6}\times 8.2\times 10^3\times sin(87)}

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So, the strength of the magnetic field is 0.042 Tesla. Hence, this is the required solution.

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Hope this helps!
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See
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so option B is the correct answer.
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