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VLD [36.1K]
3 years ago
6

Help please!! will give brainly for full answers

Physics
1 answer:
Oliga [24]3 years ago
7 0
1)it starts moving /performing random action
2)once the paper clips is pulled away from the nail it will not perform the same action ,it not hold them together it changes to force field instead of contact force
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Using the ideas from this section and the periodic table, choose the more reactive nonmetal. C or F
alexira [117]

c i hope thats the answer

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ONE sound wave travels through two containers of different gasses. Wave through container 1 has a wavelength of 1.2 m. Wave thro
Zarrin [17]
I’m not 100% but the answer is b
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2 years ago
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is
inn [45]
Two small spheres spaced 20.0 cm apart have equal charge.

How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57 x 10-21 N?

Number of Electrons = ?
5 0
3 years ago
A 4.67-g bullet is moving horizontally with a velocity of +357 m/s, where the sign + indicates that it is moving to the right (s
Leni [432]

Answer:

(a)0.531m/s

(b)0.00169

Explanation:

We are given that

Mass of bullet, m=4.67 g=4.67\times 10^{-3} kg

1 kg =1000 g

Speed of bullet, v=357m/s

Mass of block 1,m_1=1177g=1.177kg

Mass of block 2,m_2=1626 g=1.626 kg

Velocity of block 1,v_1=0.681m/s

(a)

Let velocity of the second block  after the bullet imbeds itself=v2

Using conservation of momentum

Initial momentum=Final momentum

mv=m_1v_1+(m+m_2)v_2

4.67\times 10^{-3}\times 357+1.177(0)+1.626(0)=1.177\times 0.681+(4.67\times 10^{-3}+1.626)v_2

1.66719=0.801537+1.63067v_2

1.66719-0.801537=1.63067v_2

0.865653=1.63067v_2

v_2=\frac{0.865653}{1.63067}

v_2=0.531m/s

Hence, the  velocity of the second block after the bullet imbeds itself=0.531m/s

(b)Initial kinetic energy before collision

K_i=\frac{1}{2}mv^2

k_i=\frac{1}{2}(4.67\times 10^{-3}\times (357)^2)

k_i=297.59 J

Final kinetic energy after collision

K_f=\frac{1}{2}m_1v^2_1+\frac{1}{2}(m+m_2)v^2_2

K_f=\frac{1}{2}(1.177)(0.681)^2+\frac{1}{2}(4.67\times 10^{-3}+1.626)(0.531)^2

K_f=0.5028 J

Now, he ratio of the total kinetic energy after the collision to that before the collision

=\frac{k_f}{k_i}=\frac{0.5028}{297.59}

=0.00169

5 0
3 years ago
A gas hot water heater is 65% efficient. The energy output to heat the water is 2.3 kWh.
Art [367]

Answer:

3.5 kWh

1.2 kWh are lost

Explanation:

65=2.3/Ein*100

0.65=2.3/Ein

Ein=2.3/.65

Ein=3.5

3.5-2.3=1.2 kWh

7 0
3 years ago
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