Answer:
The answer is 61.
Step-by-step explanation:
7(9)-2
63-2
61
Answer:
Step-by-step explanation:
Given y = coskt
y' = -ksinkt
y'' = -k²coskt
Substitute this y'' into the expression 25y'' = −16y
25(-k²coskt) = -16(coskt)
25k²coskt = 16(coskt)
25k² = 16
k² = 16/25
k = ±√16/25
k = ±4/5
b) from the DE 25y'' = −16y
Rearrange
25y''+16y = 0
Expressing using auxiliary equation
25m² + 16 = 0
25m² = -16
m² = -16/25
m = ±4/5 I
m = 0+4/5 I
Since the auxiliary root is complex number
The solution to the DE will be expressed as;
y = Asinmt + Bsinmt
Since k = m
y = Asinkt+Bsinkt where A and B are constants
Area of sector = PI x r^2 x (angle/360)
area = PI x 10^2 * (45/360)
area = PI x 100 * 45/360
Area = 25/2x PI
Area = 25PI/2
Answer is D
Answer:
35+2.5v = 70
so the answer is 14
Step-by-step explanation:
i solved it xD
