The number of electrons emitted from the metal per second increases if the intensity of the incident light is increased.
Answer: Option B
<u>Explanation:</u>
As a result of photoelectric effect, electrons are emitted by the light incident on a metal surface. The emitted electrons count and its kinetic energy can measure as the function of light intensity and frequency. Like physicists, at the 20th century beginning, it should be expected that the light wave's energy (its intensity) will be transformed into the kinetic energy of emitted electrons.
In addition, the electrons count emitting from metal must vary with light wave frequency. This frequency relationship was expected because the electric field oscillates due to the light wave and the metal electrons react to different frequencies. In other words, the number of electrons emitted was expected to be frequency dependent and their kinetic energy should be dependent on the intensity (constant wavelength) of light.
Thus, the maximum in kinetic energy of electrons emitted increases with increase in light's frequency and is experimentally independent of light intensity. So, the number of emitted electrons is proportionate to the intensity of the incident light.
Answer:
![v_0 = 3.53~{\rm m/s}](https://tex.z-dn.net/?f=v_0%20%3D%203.53~%7B%5Crm%20m%2Fs%7D)
Explanation:
This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.
The initial velocity is in the x-direction, and there is no acceleration in the x-direction.
On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.
Applying the equations of kinematics in the x-direction gives
![x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}](https://tex.z-dn.net/?f=x%20-%20x_0%20%3D%20v_%7Bx_0%7D%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7Da_x%20t%5E2%5C%5C63%20%5Ctimes%2010%5E%7B-3%7D%20%3D%20v_0t%20%2B%200%5C%5Ct%20%3D%20%5Cfrac%7B63%5Ctimes%2010%5E%7B-3%7D%7D%7Bv_0%7D)
For the y-direction gives
![v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t](https://tex.z-dn.net/?f=v_y%20%3D%20v_%7By_0%7D%20%2B%20a_y%20t%5C%5Cv_y%20%3D%200%20-9.8t%5C%5Cv_y%20%3D%20-9.8t)
Combining both equation yields the y_component of the final velocity
![v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}](https://tex.z-dn.net/?f=v_y%20%3D%20-9.8%28%5Cfrac%7B63%5Ctimes%2010%5E%7B-3%7D%7D%7Bv_0%7D%29%20%3D%20-%5Cfrac%7B0.61%7D%7Bv_0%7D)
Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.
![\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}](https://tex.z-dn.net/?f=%5Ctan%28%5Ctheta%29%20%3D%20%5Cfrac%7Bv_y%7D%7Bv_x%7D%5C%5C%5Ctan%28177.2%5E%5Ccirc%29%20%3D%20-0.0489%20%3D%20%5Cfrac%7Bv_y%7D%7Bv_0%7D%20%3D%20%5Cfrac%7B-0.61%2Fv_0%7D%7Bv_0%7D%20%3D%20-%5Cfrac%7B0.61%7D%7Bv_0%5E2%7D%5C%5Cv_0%20%3D%203.53~%7B%5Crm%20m%2Fs%7D)
Answer:
5.5 m/s^2
Explanation:
I believe this is the answer > using the formula a= v-v0/t
Hope this helps!
Answer:
Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.
Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.
Explanation:
Answer:
A) for leftmost point the coordinate is -0.28m that means it should be 0.28m towards the right.
B) for rightmost case the coordinate is 0.28m which is where komila should sit.
Explanation:
Detailed calculation and explanation is shown in the image below