Ask question

Ask question

All categories

3 years ago

7

A box with its contents has a total mass of 40 kg. It is dropped from a very high building. After reaching terminal speed, what

is the magnitude of the air resistance force acting upward on the falling box

2 answers:

yanalaym [24]3 years ago

4 0

Answer:

The magnitude of air = 392N

Explanation:

We use Newton's 2nd law. The sum of the vertical forces must be equal to zero because at terminal speed , the acceleration is zero. Solving for the air resistance force,F(air ) gives:

EFvertical = mg - F(air)= ma

F(air) = mg = 40 × 9.8 = 392N

Mkey [24]3 years ago

3 0

Answer: 392N

Explanation:

Newton's second law of motion states that "The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object."

the sum of vertical forces has to be equal to zero because by the time the terminal speed has been attained, the acceleration is zero. Now, we solve for air resistance force.

summation of F(vertical) = mg - F(air) = ma

a = 0 m/s²

thus, F(air) = mg

F(air) = 40kg*9.8m/s²

F(air) = 392N

You might be interested in

Consider a car engine running at constantspeed. That is, the crankshaft of the en-gine rotates at constant angular velocity whil

Irina-Kira [14]

Answer:

The value is $|v| = 7.39 \ m/s$

Explanation:

From the question we are told that

The angular speed is $w = 2030 \ rpm = \frac{2030 * 2 * \pi }{ 60} = 212.61 \ rad/s$

The distance between the minimum and maximum external position is $d = 6.95 \ cm = 0.0695 \ m$

Generally the amplitude of the crank shaft is mathematically represented as

$A = \frac{d}{2}$

=> $A = \frac{0.0695}{2}$

=> $A = 0.03475 \ m$

Generally the maximum speed of the piston is mathematically represented as

$|v| = A * w$

=> $|v| = 0.03475 * 212.61$

=> $|v| = 7.39 \ m/s$

7 0

3 years ago

The weight of an object on Earth is 350 newtons. On Mars, the same object would weigh 134 newtons. What is the acceleration due

sineoko [7]

W = mg = 350 newton
m = W/g = 350/9.8 = 35.71 kg
on mars
W = mg = 134 newton
g = W/m = 134/35.71 = 3.75 meters/second2

4 0

3 years ago

Read 2 more answers

Newton's first law states that objects do not change their velocity unless acted upon

Viefleur [7K]

Answer:

Air resistance/Drag (this is the proper term for air resistance) or gravity or friction

It depends on the direction and if you throw it across a surface or if you throw it straight upwards.

I hope this helps!!

8 0

3 years ago

Read 2 more answers

An archer fires an arrow at a castle 230 m away. The arrow is in flight for 6 seconds, then hits the wall of the castle and stic

Vika [28.1K]

Answer:

(a). The initial speed of the arrow is 49.96 m/s.

(b). The angle is 39.90°.

Explanation:

Given that,

Horizontal distance = 230 m

Time t = 6 sec

Vertical distance = 16 m

We need to calculate the horizontal component

Using formula of horizontal component

$R =u\cos\theta t$

Put the value into the formula

$\dfrac{230}{6} = u\cos\theta$

$u\cos\theta=38.33$ .....(I)

We need to calculate the height

Using vertical component

$H=u\sin\theta t-\dfrac{1}{2}gt^2$

Put the value in the equation

$16 =u\sin\theta\times6-\dfrac{1}{2}\times9.8\times6^2$

$u\sin\theta=\dfrac{16+9.8\times18}{6}$

$u\sin\theta=32.06$ .....(II)

Dividing equation (II) and (I)

$\dfrac{u\sin\theta}{u\cos\theta}=\dfrac{32.06}{38.33}$

$\tan\theta=0.8364$

$\theta=\tan^{-1}0.8364$

$\theta=39.90^{\circ}$

(a). We need to calculate the initial speed

Using equation (I)

$u\cos\theta\times t=38.33$

Put the value into the formula

$u =\dfrac{230}{6\times\cos39.90}$

$u=49.96\ m/s$

(b). We have already calculate the angle.

Hence, (a). The initial speed of the arrow is 49.96 m/s.

(b). The angle is 39.90°.

5 0

3 years ago

Identify the energy transformations in the following actions.

Artemon [7]

According to the Law of Conservation of Energy, energy is neither created nor destroyed. It is only transferred through different forms of energy. For the following situations, the conversion of energy is as follows:

*Turning on a space heater = electrical energy⇒heat energy
*Dropping an apple core into the garbage = potential energy⇒kinetic energy
*Climbing up a rope ladder = kinetic energy⇒potential energy
*Starting a car = chemical energy⇒mechanical energy
<span>*Turning on a flashlight = chemical energy</span>⇒electrical energy

4 0

3 years ago

Read 2 more answers