Answer:
a) θ = 2500 radians
b) α = 200 rad/s²
Explanation:
Using equations of motion,
θ = (w - w₀)t/2
θ = angle turned through = ?
w = final angular velocity = 1420 rad/s
w₀ = initial angular velocity = 420
t = time taken = 5s
θ = (1420 - 420) × 5/2 = 2500 rads
Again,
w = w₀ + αt
α = angular accelaration = ?
1420 = 420 + 5α
α = 1000/5 = 200 rad/s²
They have a negative oxidation number because nonmetals gain electrons, thus making them negatively charged ions (anions). Metals become cations and have a positive charge because they lose electrons.
In your question where as a golf ball is struck at a ground level and the speed of the ball as a function of time is in the figure where time t=0 and va = 16m/s and vb=32m/s. The following is the answer:
a) How far does the golf ball travel horizontally before returning to ground level?
-<span>80m</span>
<span>(b) What is the maximum height above ground level attained by the ball?
</span>-39.87m
Answer:
130.22 g
Explanation:
Parameters given:
Mass of water Mw = 225 g
Mass of stirrer Ms = 40 g
Mass of silver M(S) = 410 g
By applying the law of conservation of energy:
(McCc + MsCs + MwCw)ΔTw = M(S)C(S)ΔT(S)
where Mc = Mass of cup
Cc = Specific heat capacity of aluminium cup = 900 J/gC
Cs = Specific heat capacity of copper stirrer = 387 J/gC
Cw = Specific heat capacity of water = 4186 J/gC
ΔTw = change in temperature of water = 32 - 27 = 5 °C
C(S) = Specific heat capacity of silver = 234 J/gC
ΔT(S) = change in temperature of silver = 88 - 32 = 56 °C
Therefore:
[(Mc * 900) + (40 * 387) + (225 * 4186)] * 5 = 410 * 234 * 56
(900Mc + 957330) * 5 = 5276700
900Mc + 957330 = 5276700 / 5 = 1074528
900Mc = 1074528 - 957330
900Mc = 117198
Mc = 117198/ 900
Mc = 130.22 g
The mass of the cup is 130.22 g.
Answer:
V= 33.98 m/s
Explanation:
Given that
Horizontal speed ,u= 17 m/s
Time taken by rockets to strike the water ,t= 3 s
We know that acceleration due to gravity ,g= 9.81 m/s²
There is no any acceleration in the horizontal direction that is why the horizontal veloity will remain constant.
In the vertical direction
vy = uy+ g t
Initial velocity in vertical direction is 0 m/s.
vy= 0+ 9.81 x 3
vy = 29.43 m/s
The resultant velocity
V= 33.98 m/s
