The distance between Jupiter and the sun is 5.2 AU.
According to Kepler's third law, the square of the period of revolution of planets is proportional to the cube of their mean distances from the sun. From this; T^2 = r^3.
Now, we are told that the orbital period (T) is 11. 9 Earth years. We have to make the distance the subject of the formula.
r =T^2/3
r = (11.9)^2/3
r = 5.2 AU
Learn more: brainly.com/question/15207516
Hi there!
Acceleration:
a = Δv / Δt, so:
a = 20/9 ≈ 2.22 m/s²
Displacement:
We can use the equation Δd = v₀t + 1/2at² to solve. (Initial velocity is 0).
Δd = 1/2at²
Plug in the acceleration and time:
Δd = 1/2(2.22)(9)² ≈ 89.91 m
Work formula:
W = F * d
F 1 = 40 N, d 1 = 6 m;
F 2 = 30 N; d 2 = 6 m.
W ( Cindy ) = 40 * 6 = 240 Nm
W ( Andy ) = 30 * 6 = 180 Nm
The difference of their amounts if work:
240 Nm - 180 Nm = 60 nm
hope it helps!
