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Anuta_ua [19.1K]
3 years ago
12

Two satellites are in circular orbits around Earth. Satellite A has speed vA. Satellite B has an orbital radius nine times that

of satellite A. What is the speed of Satellite B?
A. vA.9
B. vA/3
C. 3vA
D. 9vA
Physics
1 answer:
zaharov [31]3 years ago
5 0

Answer:

option B

Explanation:

given,

Satellite B has an orbital radius nine times that of satellite A.

R' = 9 R

now, orbital velocity of the satellite A

v_a =\sqrt{\dfrac{GM}{R}}........(1)

now, orbital velocity of satellite B

v_b=\sqrt{\dfrac{GM}{R'}}

v_b=\sqrt{\dfrac{GM}{9R}}

v_b=\dfrac{1}{3}\sqrt{\dfrac{GM}{R}}

from equation 1

v_b=\dfrac{v_a}{3}

hence, the correct answer is option B

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A stun gun or TASER is designed to put out a few seconds worth of electric pulses that impress a
iren [92.7K]

Answer:

Resistance = 400000 Ohms

Explanation:

Given the following data;

Voltage = 1200 V

Current = 3 mA = 3/1000 = 0.003 A

To find the resistance;

Voltage = current * resistance

Resistance = 1200/0.003

Resistance = 400000 Ohms

5 0
3 years ago
A local AM radio station broadcasts at a frequency of 696 KHz. Calculate the energy of the frequency at which it is broadcasting
bagirrra123 [75]

Answer:

E=4.61\times 10^{-28}\ J

Explanation:

Given that,

The frequency of local AM radio station, f = 696 KHz = 696000 Hz

We need to find the energy of the frequency at which it is broadcasting.

We know that,

Energy of a wave, E = hf

Where

h is Planck's constant

Put all the values,

E=6.63\times 10^{-34}\times 696000\\\\=4.61\times 10^{-28}\ J

So, the energy of the wave is equal to4.61\times 10^{-28}\ J.

5 0
3 years ago
A net force of 50 newtons is applied to a 20 kilogram cart that is already moving at 1 m/s the final speed of the cart was 3 m/s
valina [46]

Answer:

0.8 seconds

Explanation:

F=ma

Let x be the seconds the force is applied.

m = 20kg

F = 50 Newtons (kg*m/sec^2)

acceleration, a, is provided for x seconds to increase the speed from 1 m/s to  3 m/s, an increase of 2m/s

Let's calculate the acceleration of the cart:

F=ma

(50 kg*m/s^2) = (20kg)*a

a = 2.5 m/s^2

---

The acceleration is 2.5 m/s^2.  The cart increases speed by 2.5 m/s every second.  

We want the number of seconds it takes to add 2.0 m/sec to the speed:

(2.5 m/s^2)*x = 2.0 m/s

x = (2.0/2.5) sec

x = 0.8 seconds

7 0
3 years ago
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evablogger [386]

Answer:

b

Explanation:

3 0
3 years ago
A sample of copper has a volume of 23.4 cm3 if the density of copper is 8.9 gcm3 what is the coppers mass?
murzikaleks [220]
The answer is:  " 208 g " .
_____________________________________________
Explanation:
__________________________________________
The formula/ equation for density is:
__________________________________________
D = m / V  ;  That is,  "mass divided by volume" ;
 
Density is expressed as:
__________________________________________    
                   "mass per unit volume";  in which the "mass" is expressed in units of "g" ("grams") ;  and the "unit volume" is expressed in units of:
    "cm³ " or "mL"; 
_____________________________________________
           {Note the exact equivalent:  1 cm³ = 1 mL }.
____________________________________________
         →  The formula is:  " D = m / V "  ; 
___________________________________________
   in which:

     "D" refers to the "density" (see above), which is: "8.9 g/cm³ " (given); 

     "m" refers to the "mass" , in units of "g" (grams), which is unknown; and we want to find this value;
                 
     "V" refers to the "volume", in units of "cm³ " ;
               which is:  "23.4 cm³ " (given);
_________________________________________________
                 We want to find the mass, "m" ; so we take the original equation/formula for the density:
_________________________________________________ 
              D  =  m / V ; 
_________________________________________________________
             And we rearrange; to isolate "m" (mass) on ONE side of the    equation; and then we plug in our known/given values;
 to solve for "m" (mass);  in units of "g" (grams) ;
___________________________________________________
    Multiply each side of the equation by "V" ; 
____________________________________________________
             V * { D  =  m / V } ;  to get:
____________________________________________________
      V * D = m ;   ↔   m = V * D ;
___________________________________________________
           Now, we plug in the given values for "V" (volume) and "D" (density) ;     to solve for the mass, "m" ;
______________________________________________________
           m  =  V * D ;
 
           m  =  (23.4 cm³) * (8.9 g / 1 cm³)  = (23.4 * 8.9) g = 208.26 g ;
  
 →  Round to "208 g" (3 significant figures);  
____________________________________
The answer is:  " 208 g " .
_____________________________________________________
7 0
3 years ago
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