<h3>
Answer:</h3>
13 g CO₂
<h3>
General Formulas and Concepts:</h3>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] 6.7 L O₂
[Solve] g O₂
<u>Step 2: Identify Conversions</u>
[STP] 22.4 L = 1 mol
[PT] Molar Mass of O: 16.00 g/mol
[PT] Molar Mass of C: 12.01 g/mol
Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Divide/Multiply [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
13.1637 g CO₂ ≈ 13 g CO₂
Answer:
Evaporation is a technique used to separate out homogeneous mixtures where there is one or more dissolved salts.
Explanation:
Hope this helps :)
equation is balanced when the number of molecules are the equal in both reacting side and the product side.
Li(s) + n2(g) ---> Li3n(s)
From the equation above the reaction is not balanced since the molecules are not equal in both reacting side and the product side.
The reaction is balanced by adding 6 in front of Li and 2 infront of Li3n
that is
6Li(s) + n2(g)-----> 2Li3n(s)
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Explanation:
As it is known that
molecule is a non-linear molecule. Therefore, its isochoric heat capacity will be as follows.

= 
= 18 R
Also, 
where,
= molar heat capacity
M = molecular mass
= specific heat
Hence, calculate the value of
as follows.



This means that value of isochoric specific heat is
.
Yes, we have to assume ideal gas behavior because for ideal gas:
dU = 
Whereas for real gases "
" has to be added here.