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Vladimir79 [104]
3 years ago
11

The pressure inside a hydrogen-filled container was 2.10 atm at 21 ∘C. What would the pressure be if the container was heated to

88 ∘C ?
Physics
2 answers:
ladessa [460]3 years ago
8 0

Answer:

2.58 atm

Explanation:

P1 = 2.1 atm

T1 = 21 °C = 294 K

T2 = 88 °C = 361 K

P2 = ?

By using the gas laws

P / T = constant keeping the volume constant.

P1 / T1 = P2 / T2

2.10 / 294 = P2 / 361

P2 = 2.58 atm

Thus, the pressure becomes 2.58 atm.

marissa [1.9K]3 years ago
4 0

Answer:

2.57832 atm

Explanation:

P_1 = Initial pressure = 2.1 atm

P_2 = Fianl pressure

T_1 = Initial Temperature = (21+273.15) K

T_2 = Final Temperature = (88+273.15) K

From Gay-Lussacs law we have

\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\Rightarrow P_2=\dfrac{P_1\times T_2}{T_1}\\\Rightarrow P_2=\dfrac{2.1\times (88+273.15)}{21+273.15}\\\Rightarrow P_2=2.57832\ atm

The final pressure would be 2.57832 atm

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2 years ago
A ball is kicked at an angle of 35° with the ground.a) What should be the initial velocity of the ball so that it hits a target
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b.1.98 s

Explanation:

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\theta=35^{\circ}

a.Let v_0 be the initial velocity of the ball.

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Height,h=1.8 m

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