Answer:
The answer to your question is a = 0.25 m/s²
Explanation:
Data
mass = m = 400 kg
Force = F = 100 N
acceleration = a = ? m/s²
Process
To solve this problem use Newton's second law that states that the force applied to an object is directly proportional to the mass of the body times its acceleration.
Formula
F = ma
solve for a
a = 
Substitution
Simplification and result
a = 0.25 m/s²
Answer:
You pull on the oars. By the third law, the oars push back on your hands, but that’s irrelevant to the motion of the boat. The other end of each oar (the blade) pushes against the water. By the third law, the water pushes back on the oars, pushing the boat forward.
Speed uses distance and velocity uses displacement in its calculation.
For 100 m race, distance = displacement. Hence speed = velocity
For 400m race, distance ≠ displacement. distance = 400m whereas displacement = 0m. Hence speed ≠ velocity
The electrons making the shock come from the women's body.
<h3>What is Electric shock ?</h3>
When a high voltage current flows through the body, electrical shock results. When someone unintentionally touches an electrical source, this typically occurs. Treatment for both internal and exterior burns may be necessary as part of the aftercare.
The nervous system may be impacted by a shock.
The tissue that makes up nerves presents extremely minimal resistance to the flow of an electric charge. Electric shocks that impact nerves can cause pain, tingling, numbness, weakness, or trouble moving a limb. These effects might disappear with time or remain for good.
How to Prevent from Electrical Shocks –
- Keep the Appliances Away from Moisture and Water.
- Never Connect or Disconnect Under Load.
- Be Careful with Capacitors.
- Use Insulated Tools.
- Turn Off the Power.
- Check for Improper or Faulty Wiring.
- Fix Extension Cord Problems.
to learn more about electric shock go to - brainly.com/question/8822505
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Answer: 0.2 hours
Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .
Besides, this battery has a voltage of 12 V
so by using the Ohm law we also know that V=R*I,
Fron this we can obtain:
I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA
then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA in x time in the form:
1hour------- 1800 mA
x hour--------350 mA
time= 350/1800= 0.2 hour
