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4 years ago

Please help! 100 Points to the lucky person that knows the answer! Find the value of x. (7x - 1), (6x - 1)

Mathematics

2 answers:

Harman [31]4 years ago

8 0

Hey!

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Since we know that both expressions lay on a straight line, we know that when both lines add up it should be 180°

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We can write the expression as (7x - 1) + (6x - 1) = 180

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Simplify

→ (7x + −1) + (6x + −1) = 180

Combine Like Terms

→ (7x + 6x) + (-1 + -1) = 180 → 13 + -2 = 180

Add 2 To Both Sides

→ 13x - 2 + 2 = 180 + 2 → 13x = 182

Divide 13 To Both Sides

13x/13 = 182/13 → x = 14

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Hence, the value of x is 14!

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Hope This Helped! Good Luck!

olga2289 [7]4 years ago

6 0

Answer:

Step-by-step explanation:

(7x - 1)° + (6x - 1)° = 180°

(13x - 2)° = 180°

13x = 182°

x = 182°/13

x = 14

I hope I helped you.

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3 years ago

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masya89 [10]

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$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

Translation:

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

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natta225 [31]

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4 years ago

Read 2 more answers

Please help! 100 Points to the lucky person that knows the answer! Find the value of x. (7x - 1)*, (6x - 1)*

Please help! 100 Points to the lucky person that knows the answer! Find the value of x. (7x - 1), (6x - 1)