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11 months ago

What are all the stages of mitosis? (please make it long)

1 answer:

soldier1979 [14.2K]11 months ago

3 0

Mitosis is conventionally divided into 5 phases, which include prophase, prometaphase, metaphase, anaphase and telophase and cytokinesis.

Interphase

Before coming into mitosis, a mobile spends a length of its increase underneath interphase.

Prophase

Prophase straight away follows the S and G2 levels of the cycle and is marked by way of condensation of the genetic fabric to form compact mitotic chromosomes composed of chromatids attached at the centromere.

Prometaphase

In the prometaphase, the nuclear envelop disintegrates. Now the microtubules are allowed to extend from the centromere to the chromosome.

Metaphase

At this level, the microtubules start pulling the chromosomes with equal pressure and the chromosome ends up in the center of the cell. This area is referred to as the metaphase plate.

Anaphase

The splitting of the sister chromatids marks the onset of anaphase. These sister chromatids end up the chromosome of the daughter nuclei.

Telophase

The chromosomes that cluster at the two poles start coalescing into an undifferentiated mass, because the nuclear envelope begins forming round it.

To know more about mitosis at

brainly.com/question/8757261

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I need help! how many moles are in 3.4*10^-7 grams of silicon dioxide, SiO2. I got 2.0^17 but I think it's wrong :(

blondinia [14]

Molar mass SiO2 = 28 + 32 = 60

so moles sand = 3.4 x 10-7 / 60

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3 years ago

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Irina-Kira [14]

Answer:

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1 year ago

Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, the reaction is balanced. Now, the problem give to us two amounts of reagents. Therefore, we have to find the limiting reagent. The first step then is to find the moles of each compound using the molar mass:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can divide by the coefficient of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our limiting reagent. Now, if we use the molar ratio between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the molar mass of XY would be 85+24 = 109 g/mol. With this in mind:

$0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY$

I hope it helps!

6 0

3 years ago

Which metal atoms can form ionic bonds by losing electrons from both the outermost and next to outermost principal energy levels

RoseWind [281]

Full question options;

(Fe, Pb, Mg, or Ca)

Answer:

Iron - Fe

Explanation:

We understand tht metals pretty much form bonds by losing their valence (outermost electrons). But this question specifically asks for metals that lose beyond their outermost electrons; next to outermost principal energy levels.

Pb, Mg, and Ca only lose their outermost electrons to form the following ions;

Pb2+, Mg2+, and Ca2+.

This is because their ions have achieved a stable octet configuration - the dreamland of atoms where they are satisfied and don't need to go into reactions again.

Iron on the other hand has the following electronic configurations;

Fe: [Ar]4s2 3d6

Fe2+: [Ar]4s0 3d6

Fe3+: [Ar]4s0 3d5

This means ion can lose both the ooutermost electrons (4s) and next to outermost principal energy levels (3d). So correct option is Iron.

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3 years ago

A reaction progress curve has three peaks and two valleys between the peaks. This curve describes a reaction mechanism that invo

katrin [286]

Answer:
A reaction progress curve has three peaks and two valleys between the peaks. This curve describes a reaction mechanism that involves three elementary reactions.

Explanation:
I have drawn the progress curve with three peaks and two valleys. In fact the peaks shows higher energy and valleys show lower energies. So, Let suppose we react A and B. This reaction between A and B results in the formation of C. In this reaction the energies of A and B are less, and during the progress of reaction they cross a transition state of higher energy and forms product C with lower energy which is present at lower valley. This was first reaction. Other two reactions will be followed by conversion of C to D and conversion of D into E.

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3 years ago

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