Question

A football is kicked from ground level at an angle of 38 degrees. It reaches a maximum height of 9.7 meters before returning to the ground. How long will the football spend in the air, in seconds?

Answer 1

Answer:

Football will be in air for 2.8139 sec

Explanation:

We have given maximum height h = 9.7 meters

Angle of projection $\Theta =38^{\circ}$

We know that maximum height is given by $h=\frac{u^2sin^2\Theta }{2g}$

So $9.7=\frac{u^2sin^{2}38^{\circ} }{2\times 9.8}$

$u^2=501.5842$

u = 22.396 m/sec

Time of flight is given by

$T=\frac{2usin\Theta }{g}=\frac{2\times 22.396\times \times sin38^{\circ}}{9.8}=2.8139sec$