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kkurt [141]
2 years ago
5

What magnification would be obtained if an eyepiece with a focal length of 0.38 m was placed on telescope?

Physics
1 answer:
weqwewe [10]2 years ago
7 0

Answer:

This question is incomplete

Explanation:

This question is incomplete because the telescope's focal length was not provided. The formula to be used here is

Magnification = telescope's focal length/eyepiece's focal length

The eyepiece's focal length was provided in the question as 0.38 m.

NOTE: Magnification can be described as the power of an instrument (in this case telescope) to enlarge an object. It has no unit and thus the two focal lengths mentioned in the formula above must be in the same unit (preferably meters since one of them is in meters already).

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Answer:

6.00 x 10⁻⁸N

Explanation:

Given parameters:

Mass of each dump trucks  = 1500kg

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Unknown:

New gravitational force between them = ?

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3 years ago
An instrument is thrown upward with a speed of 15 m/s on the surface of planet X where the acceleration due to gravity is 2.5 m/
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Explanation:

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y_{o}=0  is the instrument's initial position

V_{o}=15m/s is the instrument's initial velocity

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g=2.5\frac{m}{s^{2}}  is the acceleration due to gravity at the surface of planet X.

As we know y_{o}=0  and y=0 when the object hits the ground, equation (1) is rewritten as:

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Finding t:

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t=\frac{2V_{o}}{g}   (4)

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t=12s

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