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hodyreva [135]
4 years ago
6

When strongly electronegative atoms, like fluorine, bond to atoms with a lower electronegativity, like hydrogen, what's the resu

lt?
Chemistry
1 answer:
olganol [36]4 years ago
7 0
When highly electronegative element like oxygen is directly attached to less electronegative element like hydrogen the electrons from less electronegative elements are attracted toward the highly electronegative element, making the less electronegative element deficient in electron density (partial positive) and a partial negative charge on more electronegative element is created. In such situation the intermolecular forces formed are dipole-dipole interactions or hydrogen bond interaction like in HF.
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2. How will the equilibrium shift if the following changes are made? State if the reaction will shift
Kamila [148]

Please give me brainleist. :)

Answer:

2a. If the temperature is increased, the reaction will shift to the right in an attempt to release some of the heat. As the forward reaction loses heat while the reverse would create more heat.

2b. If the pressure is increased, it would shift to the left to counteract the increase in pressure as the left side will have fewer molecules.

2c. If Cl2 is added the reaction will shift to the left in order to remove the stress of the extra Cl2 and favor the production of more reactant.

2d. If PCl3 is removed, the reaction will shift to the right. When part of the equation is removed the reaction learns to adapt to the loss by trying to make more Pcl3 and counteract the effects of losing the PCl3.

3a. The reaction will shift to the right to produce more heat and counter the negative effects of losing the heat.

3b. It will shift to the left to get rid of the excess HCl being produced and form more reactant from the breakdown of the HCl.

3c. It would shift to the right in order to get rid of the excess form products from it.

3d. If pressure is decreased there will be no effect on the shift of the reaction because there is an even amount of moles of gas on each side.

4a. K=[N2O4(g0] / [NO2(g)]2

4b. (Below)

K=[N2O4(g)] / [NO2(g)]2

0.4 / 0.5(2)

0.4/0.25 = 1.6

Keq= 1.6

7 0
3 years ago
Look at the graph
Vlad [161]

Answer:

a item dropping

Explanation:

KE is movement and PE is height. As it's falling it gets KE and falls downward giving it more KE and less PE

7 0
3 years ago
How many moles of silver oxide (l) are needed to produce 4 moles of silver?
ozzi

The number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles

<h3>Stoichiometry </h3>

From the question, we are to determine the number of moles of silver oxide (I) needed to produce 4 moles of silver

First, we will write the balaced chemical equation for the decomposition of silver oxide (I)

2Ag₂O(s) → 4Ag(s) + O₂(g)

This means, 2 moles of silver oxide (I) [Ag₂O] decomposes to give 4 moles of <u>silver </u>and 1 mole of oxygen gas.

From the <em>balanced chemical equation</em>, it is easy to deduce the number of moles of silver oxide (I) that would give 4 moles of silver.

Hence, the number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles

Learn more on Stoichiometry here: brainly.com/question/18834543

7 0
3 years ago
Dana wants to determine the molar mass of magnesium hydroxide, Mg(OH)2. Which calculation should she use?
aleksandr82 [10.1K]
Answer C. is correct:

(molar mass of Mg) + (2 x molar mass of O) + (2 x molar mass of H)

:-) ;-)
3 0
3 years ago
Read 2 more answers
Which of the reactions are exothermic?
Nutka1998 [239]

Answer:

Reaction A, B, E and F are exothermic reactions.

Explanation:

Exothermic reactions are defined as the reactions in which energy of reactants is more than the energy of the products. In these reactions, energy is released by the system.

The total enthalpy of the reaction (\Delta H) comes out to be negative.

Endothermic reactions are defined as the reactions in which energy of products is more than the energy of the reactants. In these reactions, energy is absorbed by the system.

The total enthalpy of the reaction (\Delta H) comes out to be positive.

So, from the given option reaction which are exothermic are with negative value (\Delta H) that enthalpy of reaction and those are:

1) 2Mg(s) + O_2( g )\rightarrow 2MgO (s),ΔH = -1203 kJ/mol

2)NH_3 (g) + HCl (g)\rightarrow NH_4Cl (s),ΔH =-176 kJ/mol

3) C(graphite) + O_2 (g)\rightarrow CO_2 (g),ΔH = -393.5 kJ/mol

4) CH_4 (g) + 2O2 (g)\rightarrow CO_2 (g) + 2H_2O (l),ΔH =-891 kJ/mol

6 0
4 years ago
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