What evidence did Mendeleev use to decide that the alkali metals should be in the same group?

Chemistry

1 answer:

Bezzdna [24]2 years ago

4 0

Answer:

they all reacted the same

Explanation:

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slader Consider the following reactions: A. uranium-238 emits an alpha particle; B. plutonium-239 emits an alpha parti- cle; C.

pishuonlain [190]

Answer:

For A: The equation is $_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha$

For B: The equation is $_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha$

For C: The equation is $_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta$

Explanation:

Alpha decay process is the process in which nucleus of an atom disintegrates into two particles. The first one which is the alpha particle consists of two protons and two neutrons. This is also known as helium nucleus. The second particle is the daughter nuclei which is the original nucleus minus the alpha particle released.

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha$

Beta decay process is defined as the process the neutrons get converted into an electron and a proton. The released electron is known as the beta particle. In this process, the atomic number of the daughter nuclei gets increased by a factor of 1 but the mass number remains the same.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

For A: Uranium-238 emits an alpha particle

The nuclear equation for this process follows:

$_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha$

For B: Plutonium-239 emits an alpha particle

The nuclear equation for this process follows:

$_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha$

For C: Thorium-239 emits a beta particle

The nuclear equation for this process follows:

$_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta$

6 0

2 years ago

Find the [h3o ] in a sauvignon blanc with a ph of 3.24.

KengaRu [80]

Hello!

The H₃O⁺ concentration can be found using the definition of pH and clearing the equation for [H₃O⁺]. The solution has a pH lower than 7, so the Sauvignon Blanc is acid. The calculation for [H₃O⁺] is shown below:

$pH=-log [H_3O^{+}]$

$[H_3O^{+}]= 10^{-pH}=10^{-3,24}=0,00058M$

So, the concentration of H₃O⁺ in a Sauvignon Blanc with a pH of 3,24 is 0,00058 M

Have a nice day!

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2 years ago

DDT was banned from use as a pesticide in the United States because

Dmitry_Shevchenko [17]

Too much money and dangerous

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2 years ago

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mrs_skeptik [129]

Answer:1. Energy 2. Medium 3. Original position 4. Waves 5. Matter

Explanation:

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