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daser333 [38]
3 years ago
12

Two identical space probes are orbiting Jupiter. Scientists determine that one of the space probes has a larger gravitational fo

rce acting on it than the other. which of the following is the most likely reason for the difference?
A. One space probe reached Jupiter before the other.
B. One space probe has more air resistance than the other.
C. Only one space probe is exerting a gravitational force on the other.
D. One space probe is closer to Jupiter than the other
Physics
2 answers:
Gekata [30.6K]3 years ago
7 0

Answer:

The correct answer is D

Explanation:

galina1969 [7]3 years ago
6 0

If the probes are identical, then the one that feels a larger gravitational
force is orbiting closer to Jupiter than the other one is.

If they're not identical, then the one with greater mass will feel more
gravitational force than the one with less mass, even if they're both
the same distance from Jupiter.  (We know this from the experimental
observation that fatter people weigh more, even on Earth.)
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A launched hopper reach to 1.20 m maximum height. How much is it’s launch velocity?
garri49 [273]

The launch velocity is 4.8 m/s

Explanation:

We can solve this problem by applying the law of conservation of energy. In fact, the mechanical energy of the hopper (equal to the sum of the potential energy + the kinetic energy) is conserved. So we can write:

U_i +K_i = U_f + K_f

where:

U_i is the initial potential energy, at the bottom

K_i is the initial kinetic energy, at the bottom

U_f is the final potential energy, at the top

K_f is the final kinetic energy, at the top

We can rewrite the equation as:

mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2

where:

m is the mass of the hopper

g=9.8 m/s^2 is the acceleration of gravity

h_i = 0 is the initial height

u is the launch speed of the hopper

h_f = 1.20 m is the maximum altitude reached by the hopper

v = 0 is the final speed (which is zero when the hopper reaches the maximum height)

Solving the equation for u, we find the launch speed of the hopper:

u=\sqrt{2gh_g}=\sqrt{2(9.8)(1.20)}=4.8 m/s

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4 0
3 years ago
Give examples of not useful high friction
Tatiana [17]
Friction can be bad by being too strong or too weak. 

<span>Sometimes, when it is too strong, it decreases efficiency since some energy is wasted and turns to heat. Friction can also d</span><span>amage equipment/objects like when you slide it on the floor.
</span>
When friction is too weak, like for instance when there is black ice- our center of gravity is displaced too quickly and we can fall. Likewise, if there is a lot of slush on the ground, cars can slip and slide.
6 0
3 years ago
Which if the following doesn't cause an object to accelrate it's q 4
Slav-nsk [51]

B. Constant velocity


6 0
3 years ago
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What is the slope of the line plotted below?<br> A. 1.33<br> B. -1.33<br> C. -0.6<br> D. 0.6
Naya [18.7K]

Answer:

C. -0.6

Explanation:

Line is passing through the points ( - 3, 1) & (2, - 2)

Slope of line

=  \frac{ - 2 - 1}{2 - ( - 3)}  =  \frac{ - 3}{2 + 3}  =  \frac{ - 3}{5}  =  - 0.6 \\

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3 years ago
Heavy crate sits at rest on the floor of a warehouse. you push on the crate with a force of 400 n, and it doesn't budge. what is
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Heavy crate sits at rest on the floor of a warehouse. you push on the crate with a force of 400 N, and it doesn't budge. The magnitude of the friction force on the crate in Newton is 400N

This is due to Friction force, which is defined as the resisting force that acts on a body when it is at rest (Static friction) or when it is in motion (Kinetic friction).

When a force is applied on a stationary body, the force of static friction starts to act on the body which prevents any relative motion between the object and surface. The magnitude of friction increases up to μsN, where μs is the coefficient of static friction. As the crate didn't budge, it means the amount of force applied was less than μsN. Hence the force applied was canceled by an equal and opposite amount of frictional force which was equal to 400N.

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1 year ago
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