Answer:
When they are connected in series
The 50 W bulb glow more than the 100 W bulb
Explanation:
From the question we are told that
The power rating of the first bulb is 
The power rating of the second bulb is 
Generally the power rating of the first bulb is mathematically represented as
Where 
is the normal household voltage which is constant for both bulbs
So
substituting values
Thus the resistance of the second bulb would be evaluated as
From the above calculation we see that
This power rating of the first bulb can also be represented mathematically as
This power rating of the first bulb can also be represented mathematically as
Now given that they are connected in series which implies that the same current flow through them so
This means that
So when they are connected in series
This means that the 50 W bulb glows more than the 100 \ W bulb
Answer:
Option 4
Explanation:
During heating actually heat transfer takes place from a body at higher temperature to a body at lower temperature and the heat transfer takes place until both attain the same temperature
Therefore heat transfer depends on the temperature of the systems
Now while comparing the thermal energies of the systems, if both the systems have same mass then the system which is at higher temperature has greater thermal energy when compared to the system which is at lower temperature
So in this case assuming that both the systems have same mass then the energy will leave the system with greater thermal energy and go into the system with less thermal energy as the system with greater thermal energy in this case will be at higher temperature and we are considering this assumption because thermal energy not only depends on temperature but also depends on mass of the system
Answer:
The answer to your question is below
Explanation:
Data
light speed = 300 000 km/s
a) Express it in scientific notation
to do it, we just move the decimal point 5 places to the left
300 000 = 3.0 x 10 ⁵ km/s
b) Convert this value to meters per hour
(300 000 km/s)(1000 m/1 km)(3600 s/1 h) = 300000x1000x3600 / 1x1x1
= 1.08 x 10¹² m/h
c) What distance in centimeters does light travel in 1 s?
data
v = 300 000 km/s
d = ?
t = 1 s
formula v = d/t we clear distance d = vxt
d = 300000 x 1 = 300000 km
d = 300000000 m = 30000000000 cm
P1v1/t1 = p2v2/t2
p(0.5 m^3)/(20+273 K) = pv2/(45+273 K)
find v2
