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daser333 [38]
3 years ago
12

Two identical space probes are orbiting Jupiter. Scientists determine that one of the space probes has a larger gravitational fo

rce acting on it than the other. which of the following is the most likely reason for the difference?
A. One space probe reached Jupiter before the other.
B. One space probe has more air resistance than the other.
C. Only one space probe is exerting a gravitational force on the other.
D. One space probe is closer to Jupiter than the other
Physics
2 answers:
Gekata [30.6K]3 years ago
7 0

Answer:

The correct answer is D

Explanation:

galina1969 [7]3 years ago
6 0

If the probes are identical, then the one that feels a larger gravitational
force is orbiting closer to Jupiter than the other one is.

If they're not identical, then the one with greater mass will feel more
gravitational force than the one with less mass, even if they're both
the same distance from Jupiter.  (We know this from the experimental
observation that fatter people weigh more, even on Earth.)
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A) Khi nào một vật được coi là chuyển động ? Cho ví dụ ?
Lady bird [3.3K]

Answer: ) Khi nào một vật được coi là chuyển động ? Cho ví dụ ?

b) Khi nào một vật coi là đứng yên? Cho ví dụ ?

c) Theo em câu phát biểu “ Khi khoảng cách từ vật đến vật mốc không thay đổi theo thời gian thì vật đứng yên so với vật mốc”. Có luôn đúng không, vì sao?

Explanation:

3 0
2 years ago
what is the orbital speed for a satellite 3.5 x 10^8m from the center of mars? Mars mass is 6.4 x 10^23 kg
adell [148]

Answer:

v = 349.23 m/s

Explanation:

It is required to find the orbital speed for a satellite 3.5\times 10^8\ m from the center of mass.

Mass of Mars, M=6.4\times 10^{23}\ kg

The orbital speed for a satellite is given by the formula as follows :

v=\sqrt{\dfrac{GM}{r}} \\\\v=\sqrt{\dfrac{6.67\times 10^{-11}\times 6.4\times 10^{23}}{3.5\times 10^8}} \\\\v=349.23\ m/s

So, the orbital speed for a satellite is 349.23 m/s.

6 0
3 years ago
A steam turbine operates at a boiler temperature of 450 k and an exhaust temperature of 300 k. what is the maximum theoretical e
Helga [31]
The maximum theoretical efficiency of the system is the one corresponding to the efficiency of a Carnot cycle operating between the same temperatures of the system:
\eta=1- \frac{T_c}{T_h}
where T_c and T_h are the cold and hot temperatures, respectively.
In our problem, T_c=300 K and T_h=450 K, therefore the maximum theoretical efficiency is
\eta=1- \frac{300 K}{450 K}=0.33
So, 33%.
5 0
3 years ago
o illustrate the work-energy concept, consider the case of a stone falling from xi to xf under the influence of gravity. Using t
Phantasy [73]

Answer: force of gravity on the body due to height difference above the earth's surface

Explanation: as you increase the height of a body above ground, you do work against gravity in moving it from a point on the earth's surface to that point. So a body falling has a stored up gravito-potential energy which acts on it downward due to its mass, accelerating it downwards

Answer b): kinetic energy of the body

Explanation: the downward force produces an acceleration of magnitude 9.81m/s2 downwards which means an increasing velocity. This increasing velocity means the kinetic energy of the body is increasing (kinetic energy is proportional to velocity of the body squared)

5 0
3 years ago
Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where l
goblinko [34]

Answer:

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Explanation:

The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.

\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}

where,

Δt = required time interval = ?

Δs = distance between ears = 18 cm = 0.18 m

v = speed of sound = 340 m/s

Therefore,

\Delta t = \frac{0.18\ m}{340\ m/s}

<u>Δt = 5.29 x 10⁻⁴ s = 0.529 ms</u>

4 0
3 years ago
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