Answer:
The answer is actually a. Cathode
Explanation:
Just took the quiz
If the acceleration is constant (negative or positive) the instantaneous acceleration cannot be
Average acceleration: [final velocity - initial velocity ] /Δ time
Instantaneous acceleration = d V / dt =slope of the velocity vs t graph
If acceleration is increasing, the slope of the curve at one moment will be higher than the average acceleration.
If acceleration is decreasing, the slope of the curve at one moment will be lower than the average acceleration.
If acceleration is constant, the acceleration at any moment is the same, then only at constant accelerations, the instantaneuos acceleration is the same than the average acceleration.
Constant zero acceleration is a particular case of constant acceleration, so at constant zero acceleration the instantaneous accelerations is the same than the average acceleration: zero. But, it is not true that only at zero acceleration the instantaneous acceleration is equal than the average acceleration.
That is why the only true option and the answer is the option D. only at constant accelerations.
Use the formular d = v x t
d = 2m
v= 100m/s
t= d / v
= 2 / 100
= 0.02sec
The work done to push the refrigerator is 500 Nm.
Explanation:
Work done is the measure of force required to move any object from one point to another. So it is calculated as the product of force and displacement.
If the force increases the work done will increase and similarly, the increase in displacement increases the work done. So to push the refrigerator work should be done on the object and not by the object.
As the force is 100 N and the displacement is 5 m then, work done can be measured as
Work = Force × Displacement
Work = 100 × 5 = 500 Nm
So the work done to push the refrigerator is 500 Nm.
Answer:
Explanation:
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