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PilotLPTM [1.2K]
3 years ago
11

Why does light change its velocity (or slows down) when it encounters a glass lens?​

Physics
1 answer:
Rufina [12.5K]3 years ago
6 0

Explanation:

what happens is that light slows down when it passes from the less dense air into the denser glass or water. This slowing down of the ray of light also causes the ray of light to change direction. It is the change in the speed of the light that causes refraction.

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Assuming that 50% of the initial kinetic energy of the bullet is converted into thermal energy in the bullet and the specific he
DedPeter [7]

Answer:

\Delta T=\frac{v_{i}^{2}}{4c}

Explanation:

Let the mass of bullet is m, initial velocity of bullet is vi and c be the specific heat of the bullet.

Kinetic energy, K = 1/2 mvi^2

According to the question, 50% of the kinetic energy is equal to the heat energy absorbed by the bullet.

50% of K = mass of bullet x specific heat x rise in temperature

1/4 mvi^2 = m x c x ΔT

\Delta T=\frac{v_{i}^{2}}{4c}

8 0
4 years ago
A plane mirror forms a virtual image. give reasons ​
xenn [34]

Answer:

1. The reason why a plane mirror forms a virtual image is because it doesn't let the light go through it, but it reflects the light, so if you go behind the plane mirror, then you won't see the rays of light since it's not letting the rays of light go behind it.

2. The image cannot be projected onto a screen also.

3. Also, the Rays of light never meet at a focus point, so hence, this is why the plane mirror forms a virtual image.

Thanks!

4 0
2 years ago
Read 2 more answers
As an airplane is taking off at an airport its position is closely monitored by radar. The following three positions are measure
Sergeeva-Olga [200]

Answer: acceleration a = 25m/s^2

Explanation:

Given that:

The plane travels with constant acceleration

x1 = 241.22 m at t1 = 3.70 s

x2 = 297.60 m at t2 = 4.20 s

x3 = 360.23 m at t3 = 4.70 s.

We need to calculate the velocity in the two time intervals.

Interval 1:

Average Velocity v1 = ∆x/∆t = (x2 - x1)/(t2-t1)

v1 = (297.60-241.22)/(4.20-3.70) = 112.76m/s

Interval 2:

Average Velocity v2 = ∆x/∆t = (x3-x2)/(t3-t2)

v2 = (360.23-297.60)/(4.70-4.20)

v2 = 125.26m/s

Acceleration:

Acceleration a = ∆v/∆t

∆v = v2-v1 = 125.26m/s-112.76m/s = 12.5m/s

∆t = change in average time of the two intervals = (t3-t1)/2 = (4.70-3.70)/2 = 0.5s

a = 12.5/0.5 = 25m/s^2

4 0
3 years ago
Assuming a nearly frictionless ride, what can you say about a roller coaster’s potential and kinetic energy from the top to the
ArbitrLikvidat [17]
The mechanical energy of the roller coaster is sum of kinetic energy K and gravitational potential energy U:
E=K+U
where
K= \frac{1}{2}mv^2 is the kinetic energy
U=mgh is the gravitational potential energy

Since the ride is frictionless, the total mechanical energy E is conserved during the ride. Therefore, at the top of the hill, the potential energy is maximum, because h (the height) is maximum, and this means the kinetic energy is minimum (because the sum of K and U is constant), so the velocity will be minimum. Viceversa, at the bottom of the hill, the potential energy will be minimum (because h is minimum), so the kinetic energy K will be maximum, and the velocity v of the roller coaster will be maximum.
4 0
3 years ago
If you toss a ball vertically upward in a uniformly moving train, it returns to its starting place. Will it do the same if the t
gogolik [260]

Answer:No

Explanation:

No

As the train is accelerating so train velocity will be more as compared to the ball  and thus will cover more distance as compared to the ball.

When the ball is thrown upward with some velocity, it also possesses the train velocity at the time of throwing but as time passes velocity of train increases due to acceleration of the train. This causes the ball to fall behind the point of launch.

3 0
4 years ago
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