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PilotLPTM [1.2K]
3 years ago
11

Why does light change its velocity (or slows down) when it encounters a glass lens?​

Physics
1 answer:
Rufina [12.5K]3 years ago
6 0

Explanation:

what happens is that light slows down when it passes from the less dense air into the denser glass or water. This slowing down of the ray of light also causes the ray of light to change direction. It is the change in the speed of the light that causes refraction.

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Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm
mihalych1998 [28]

Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm.?

Point a is at the center of the square, and point b is at the empty corner closest to q2. Take the electric potential to be zero at a distance far from both charges.  

(a) What is the electric potential at point a due to q1 and q2?  

(b) What is the electric potential at point b?

(c) A point charge q3 = -6.00 μC moves from point a to point b. How much work is done on q3 by the electric forces exerted by q1 and q2?

Answer:

a) the potential is zero at the center .

Explanation:

a) since the two equal-magnitude and oppositely charged particles are equidistant

b)(b) Electric potential at point b, v = Σ kQ/r

r = 5cm = 0.05m

k = 8.99*10^9 N·m²/C²

Q = -2 microcoulomb

v= (8.99*10^9) * (2*10^-6) * (1/√2m - 1) / 0.0500m

v =  -105 324 V

c)workdone = charge * potential

work = -6.00µC * -105324V

work = 0.632 J

6 0
3 years ago
Which is the correctly balanced equation for the reaction of rust, Fe2O3, and hydrochloric acid, HCl?
Mariana [72]

Answer: Option (c) is correct answer.

Explanation:

The given reaction equation is as follows.

          Fe_{2}O_{3} + HCl \rightarrow FeCl_{3} + H_{2}O

The number of atoms on reactant side are as follows.

  • Fe = 2
  • O = 3
  • H = 1
  • Cl = 1

The number of atoms on product side are as follows.

  • Fe = 1
  • O = 1
  • H = 2
  • Cl = 3

Therefore, in order to balance the equation we will balance the number of atoms in both reactant and product side.

Since number of Fe atoms in reactant side is 2, therefore, multiply FeCl_{3} by 2 in the product side.

Number of O atoms in reactant side is 3, therefore, multiply H_{2}O by 3 in the product side.

Now, the number of H atoms on product side is 6, therefore, multiply HCl by 6 in the reactant side.

The number of chlorine atoms on both reactant and product side equals 6.

Thus, the equation will become as follows.

             Fe_{2}O_{3} + 6HCl \rightarrow 2FeCl_{3} + 3H_{2}O

Hence, the equation is balanced.

5 0
3 years ago
Read 2 more answers
A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the spe
lana [24]

Answer: V = 15 m/s

Explanation:

As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

Where

F = observed frequency

f = source frequency

C = speed of light = 3×10^8

V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

300000014.7 - 1.000000049V = 3×10^8

Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

The speed of the car is 15 m/s approximately

3 0
3 years ago
According to newton's first law, what is required to make an object slow down?
Luden [163]
I believe it is friction

3 0
3 years ago
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Astar begins as a blank a large cloud of gas and dust
crimeas [40]
This is a statement but yes a star forms inside nebulae which are gigantic clouds of gas. stars form inside as the gases own gravity pulls it together after which it becomes large enough to perform fusion and become a star.
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