2 ways weak nuclear forces and gravity are alike PLEASE HELP ):
1 answer:
You might be interested in
Answer:
The maximum height of the stadium is 151.3 feet
Explanation:
Please see the attached figure for a graphical description of the problem
The equation that describes a parabolic motion is:
r = (x0 + v0 t cos θ ; y0 + v0 t sin θ + 1/2 g t²)
where:
r = position vector
x0 = initial horizontal position
v0 = initial speed
θ = launching angle
y0 = initial vertical position
t = time
g = vertical acceleration due to gravity.
First, let´s find how much time the ball travels to reach a horizontal displacement of 565 feet.
The module of the rx vector (see figure) is the distance from home to the back wall of the stadium:
rx =(x0 + v0 t cos θ ; 0)
module of rx = = 565 feet
565 feet = x0 + v0 t cos θ (considering home as initial position, x0 = 0)
565 feet / v0 cos θ = t
565 feet / 176 feet/s cos 35° = t
t = 3.92 s
With this new data, we can now calculate the module of the y-component of the vector r at time t = 3.92, which is the time at which the ball travels 565 feet in the horizontal.
The y-component of vector r is:
ry =(0 ; y0 + v0 t sin θ + 1/2 g t²)
module of ry = = back wall height (h)
h = y0 + v0 t sin θ + 1/2 g t²
Replacing with the data:
h = 3 ft + 176 ft/s * 3.92 s* sin 35° + 1/2 * (-32.2 ft/s²) * (3.92 s)²
<u>h = 151.3 ft</u>
Answer:
The answer is
<h2>3 m/s</h2>Explanation:
The speed of an object given it's kinetic energy and mass can be found by using the formula
where
KE is the kinetic energy
m is the mass
v is the speed
From the question
KE = 31,500 J
m = 7000 kg
The speed is
We have the final answer as
<h3>3 m/s</h3>Hope this helps you