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Leokris [45]
3 years ago
13

A student drove to the university from her home and noted that the odometer reading of her car increased by 12.0 km. The trip to

ok 18.0 min. (a) What was her average speed
Physics
1 answer:
Rudik [331]3 years ago
3 0

Answer:

Her average speed was 40 km/h.

Explanation:

Hi there!

The average speed (a.s) is calculated as the traveled distance divided by the time it took to cover that distance:

a.s = d/t

Where:

d = traveled distance.

t = time.

In this case, the odometer reading of the car increased by 12.0 km, which means that the distance traveled is 12.0 km. The time it took the student to cover that distance is 18.0 min (18.0 min · 1 h/60 min = 0.3 h) . Then the average speed will be:

a.s = d/t

a.s = 12.0 km/ 0.3 h

a.s = 40 km/h

Her average speed was 40 km/h.

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A typical 12-V car battery can deliver about 750,000 C of charge before dying. This is not a lot of charge. As a comparison, cal
dimaraw [331]

Answer:

3.982 kg

Explanation:

The latent heat of vaporization = 540 cal/g

= 5.4 ×10⁵ cal/kg

L = 5.4 ×10⁵ × 4.19

  = 2.26 × 10⁶ J/kg

Q = 12 × 750,000

= 9, 000, 000

= 9 × 10⁶ J

the maximum number of kg of water (at 100 degrees Celsius) that could be boiled into steam (at 100 degrees Celsius) is:

= \frac{ 9*10^6}{2.26*10^6 }

= 3.982 kg

6 0
3 years ago
if a person can jump maximum along distance of 3m ,on the earth how far could be jump on the moon where acceleration due to grav
allochka39001 [22]

Answer:

The person can jump 48 m on the Moon

Explanation:

The question parameters are;

The maximum long jump distance of a person on Earth, R_{max} = 3 m

The acceleration due to gravity on the Moon = 1 ÷ 16 of that on Earth

The distance the person can jump on the Moon is given as follows;

A person performing a jump across an horizontal distance on Earth (under gravitational force) follows the path of the motion of a projectile

The horizontal range, R_{max}, of a projectile motion is found by using the following formula

R_{max} = \dfrac{u^2}{g}

Where;

g = The acceleration due to gravity = 9.8 m/s²

Therefore, we have;

R_{max} = 3 \, m = \dfrac{u^2}{9.8 \, m/s^2 }

u² = 3 m × 9.8 m/s² = 29.4 m²/s²

Therefore, on the Moon, we have;

The acceleration due to gravity on the Moon, g_{Moon} = 1/16 × g

∴ g_{Moon} = 1/16 × g = 1/16 × 9.8 m/s² ≈ 0.6125 m/s²

R_{max \ Moon} = \dfrac{u^2}{g_{Moon}}   = \dfrac{29.4 \ m^2/s^2}{0.6125 \, m/s^2 } \approx 48 \, m

The maximum distance the person can jump on the Moon with the same velocity which was used on Earth is R_{max \ Moon} ≈ 48 m

8 0
3 years ago
A force does 30000 J of work along a distance of 9.5m. Find the applied force.
Elina [12.6K]

Answer: F=3158N

Explanation:

Work is the product of force applied and the distance the object moves along the force applied. Work is measured in joules and the equation is as follows

W = F x d

So that F = W/d

F = 30000 J / 9.5m

F = ~3158 N

8 0
3 years ago
A force of 5.00 N to the left causes a 1.35 kg book to have a net acceleration of 0.76 m/s2 to the left. What is the frictional
Nuetrik [128]

Answer:

4.0 N

Explanation:

Sum the forces in the x direction:

∑F = ma

F − Fr = ma

Fr = F − ma

Fr = 5.00 N − (1.35 kg) (0.76 m/s²)

Fr = 4.0 N

8 0
3 years ago
Communicating results allows scientists to learn from each other's results.
sveta [45]

True, scientists often talk to each other to figure out if their results were similar and what they could have done better.

Although, talking to other scientists does have risks, other scientists could copy your work and further better it.

So, your final answer is TRUE, sorry for the long answer, I needed to have a word count about 20 characters and then I got carried away! lol

3 0
3 years ago
Read 2 more answers
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