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ipn [44]
3 years ago
5

If f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (–6, 8) must also be a

point on the graph?
A. Since the function is even, the output of a negative x-value and its opposite is the same.
B. Since the function is even, the output of a negative y-value and its opposite is the same.
C. The graph has rotational symmetry, so the point will be reflected across the y-axis.
D. The graph has rotational symmetry, so the point will be rotated 90 degrees about the origin.
Mathematics
2 answers:
Jlenok [28]3 years ago
7 0
Since the function is even the outputs of a negative x-value and positive x-value are the same.
ch4aika [34]3 years ago
5 0

Definition: A function is "even" when f(x) = f(−x) for all x.

Geometrically speaking, the graph face of an even function is symmetric with respect to the y-axis, meaning that its graph remains unchanged after reflection about the y-axis.

If point (6, 8) is one the points on the graph of f(x), then f(6)=8 and since function is even, you can state that f(-6)=f(6)=8. This means that point (-6,8) must also be a point on the graph. Geometrically it means that the output of a negative x-value and its opposite is the same.

Answer: correct choice is A.

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Answer:

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<=>

-6n + 27 = -15

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-6n = -42

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Hope this helps!

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SSSSS [86.1K]

Answer:

3600

Step-by-step explanation:

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7 0
4 years ago
In the given figure, mBC =118°, mBE=76°, and m
levacccp [35]

Answer:

Correct option: A

Step-by-step explanation:

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mBDC = (1/2) * mBC

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From the secants relation in a circle, we have that:

mA = (1/2) * (mBC - mDE)

35 = (1/2) * (118 - mDE)

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The sum of the arcs is 360°, so we have:

mBC + mCD + mDE + mBE = 360

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The angles mCBD and mBDC are equal, so the triangle is isosceles.

Correct option: A

3 0
3 years ago
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