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Zigmanuir [339]
3 years ago
14

For each of the following, describe the relationship as directly or inversely proportional:

Physics
1 answer:
Maksim231197 [3]3 years ago
7 0
The relationships can best be described as follows:
As frequency increases, wavelength decreases. <span>The greater the </span>energy<span>, the larger the frequency </span>and<span> the shorter (smaller) the </span>wavelength<span>. </span>

<span>a) wavelength vs. frequency = inversely proportional
b) wavelength vs. energy = inversely proportional
c) frequency vs. energy = directly proportional

Hope this answers the questions. Have a nice day. Feel free to ask more questions.</span>
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A thin stream of water flows smoothly from a faucet and falls straight down. at one point the water is flowing at a speed of v1
kati45 [8]
<span>The formulas are, v1d1² = v2d2² ........ (1) h = (v2²-v1²)/2g ...... (2) Given that, v1 = 1.71 m/s we assume that the stream has decreased by a factor d2 =0.805d1 then, v1d1² = v2 (0.805d1)² cancelled both side d1² then we get, v1 = v2 (0.805)² v1 = v2 (0.648025) Sub v1 = 1.71, 1.71 = v2 (0.648025) v2 = 1.71/0.648025 v2 = 2.638787083831642 v2 = 2.64 m/s The vertical distance formula, h = (v2²-v1²)/2g We know that value of gravity constant is 9.8 m/s² h = {(2.64)² - (1.71)²)/2(9.8) h = {(6.9696) - (2.9241)}/19.6 h = (4.0455)/19.6 h = 0.2064030612244898 h = 0.21 cm Therefore, the vertical distance h = 0.21 cm.</span>
8 0
3 years ago
If NEPA charges 5k per kWh, what is the cost of
tiny-mole [99]

Answer:

24k

Explanation:

We multiply by 200V by 24

8 0
3 years ago
The equation of the line perpendicular to the y-axis that passes through the point (–5, 1) is y = 1. True or false.
lara31 [8.8K]

That's true. 

If the line is perpendicular to the y-axis, then it's horizontal,
and parallel to the x-axis. 

Every point on the line has the same y-coordinate.  If the point  (-5, 1) 
is on the line, then all the points  (any number, 1) are also on it. 
The equation of the line is 
                                               [ y = 1 ] .

8 0
3 years ago
As the temperature of a blackbody increases, what happens to the peak wavelength of the light it radiates
lidiya [134]

Answer:

The peak wavelength of the light it irradiates decreases

Explanation:

As the temperature of a blackbody increase, the peak wavelength of the light it radiates decreases, this follows Wien's Law.

A blackbody is an ideal substance that emits all frequencies of light and also has the ability to absorb them as well.

Wiens displacement law, explains that the position of the peak wavelength of the thermal radiation emitted by bodies can change with temperature, and as the temperature increases beyond a certain point, the wavelength begins to reduce. This often changes the colour of the light emitted from heated objects.

3 0
3 years ago
Read 2 more answers
When an excited electron falls from n = 3 to n = 2, a red radiation in the Balmer series emitted. What is the frequency of this
vichka [17]

Answer:

The frequency of this photon is 4.57\times10^{14}\ Hz

(D) is correct option.

Explanation:

Given that,

Excited states,

n=3

n=2

We need to calculate the wavelength

Using formula for energy

E=13.6(\dfrac{1}{n^2}-\dfrac{1}{m^2})

E=13.6(\dfrac{1}{4}-\dfrac{1}{9})

E=1.888\ eV

E=1.888\times1.6\times10^{-19}\ J

E=3.0208\times10^{-19}\ J

We need to calculate the frequency

Using formula of frequency

E=hf

f=\dfrac{E}{h}

Where, E =energy

f=\dfrac{3.0208\times10^{-19}}{6.63\times10^{-34}}

f=4.57\times10^{14}\ Hz

Hence, The frequency of this photon is 4.57\times10^{14}\ Hz

4 0
3 years ago
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