The speed of the sound wave in the medium, given the data is 3900 m
<h3>Velocity of a wave </h3>
The velocity of a wave is related to its frequency and wavelength according to the following equation:
Velocity (v) = wavelength (λ) × frequency (f)
v = λf
With the above formula, we can obtain the speed of the sound wave. Details below:
<h3>How to determine speed of the sound wave</h3>
The speed of the wave can be obtained as illustrated below:
- Frequency (f) = 600 Hz
- Wavelength (λ) = 6.5 m
- Velocity (v) =?
v = λf
v = 6.5 × 600
v = 3900 m
Thus, the speed of the sound wave in the medium is 3900 m
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The unit of measurement of work is the Joules. B.
Answer:
106.03 meters
Explanation:
The height is given by the formula for motion under the influence of gravity.
h = -4.9t^2 +162.7
Height is 0 when ...
0 = -4.9t^2 +162.7
4.9t^2 = 162.7
t^2 = 162.7/4.9
t = √(162.7/4.9)
The horizontal distance traveled in that time is ...
(18.4 m/s)√(162.7/4.9) s ≈ 106.03 m
The object will strike the ground about 106.03 meters from the base of the cliff.
Answer:
Explanation:
Use the one-dimensional equation:
which says that the final velocity of a falling object is equal to its initial velocity times the acceleration of gravity times the time it takes to fall. We have the final velocity, -14.5 (negative because its direction is down and down is negative), initial velocity is 0 (because it was held still by someone before it was dropped), and acceleration is -9.8 (negative again, because direction is down while acceleration increases). Filling in:
-14.5 = 0 - 9.8t and
-14.5 = -9.8t so
t = 1.5 seconds
Answer:
The acceleration of the ball is 
Explanation:
From the question we are told that
The maximum height the ball reachs is 
The horizontal component of the initial velocity of the ball is
The vertical component of the initial velocity of the ball is 
The vertically motion of the ball can be mathematically represented as

Here the final velocity at the maximum height is zero so 
Making the acceleration
the subject we have

substituting values


The negative sign shows that the direction of the acceleration is in the negative y-axis