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Molodets [167]
3 years ago
12

A 2.00-kg ball is moving at 2.20 m/s toward the right. It collides elastically with a 4.00-kg ball that is initially at rest. 1)

Calculate the final velocity of the 2.00-kg ball. (Express your answer to three significant figures.)
Physics
1 answer:
loris [4]3 years ago
7 0
Elastic collision is when kinetic energy before = kinetic energy after

Ek= 1/2mv^2

total before
Ek=1/2(2)(2.2^2) = 4.84 J

total after
Ek= 1/2(2+4)(v^2) = 3v^2

Before = after
4.84=3v^2 | divide by 3
121/75 = v^2 | square root both sides
v=1.27 m/s
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sergiy2304 [10]

Answer:

h = 4 in

Explanation:

GIVEN DATA:

volume of tin= 16 \pi

we know that

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so,

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16 = r^2 h

r = \sqrt{\frac{16}{h}}

construct formula for surface area

S = 2\pi r^2 +  2\pi rh

S = \frac{2v}{h} + 2 \sqrt{v \pi h}

minimize the function wrt  h

S' = \frac{2v}{h^2} + \sqrt{\frac{v \pi}{h} =  0

solving for h we have

h = [\frac{4 v}{\pi}]^{1/3}

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8 0
3 years ago
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malfutka [58]

Answer:

lower

Explanation:

The lower the value of the coefficient of friction, the lower the resistance to sliding.

The coefficient of friction is the ratio of the frictional force and the normal force pressing two surfaces in contact together.

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U is the coefficient of friction

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7 0
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Sauron [17]

Answer:

x = 2

Explanation:

if it was -7 = the square root of both 2x-9 together, it would be false.

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°°°°°°°°°

-7 = √2x - 9

-√2x = -9 + 7

√-2x = -2

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4 0
3 years ago
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8500 Hz and Longitudinal


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4 0
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Answer:

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Explanation:

I hope this helps! Have a good day!

5 0
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