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IRINA_888 [86]
4 years ago
5

State ohm’s law Q.34.7

Physics
1 answer:
defon4 years ago
4 0

Ohm's law states that: V=RI

Explanation:

Ohm's law states that in a conductor, the potential difference across the conductor is directly proportional to the current flowing through it. Mathematically,

V \propto I

where

V is the potential difference

I is the current

The constant of proportionality is called resistance (R), and it gives a measure of "how much the conductor opposes" to the flow of current. Therefore Ohm's law can be rewritten as

V=RI

where R is the resistance. By rewriting the equation as

I=\frac{V}{R}

we see that the larger the resistance, the lower the current in the conductor.

Learn more about Ohm's law:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

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A toy cart moves with a kinetic energy of 30 J. If its speed is doubled, what is its kinetic energy?
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Explanation:

KE is directly proportional to the square of velocity / speed.

if speed is 2 times (doubled) the KE will be

{2}^{2}

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kirill115 [55]
The answer would be reflected.
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A body of mass 400 kg is suspended at a lower end of a light vertical chain and is being pulled up vertically. Initially the bod
yKpoI14uk [10]

Answer:31.62 m/s

Explanation:

Given

mass of body m=400 kg

Pull on chain is F_1=6000g N=60 kN

Pull get smaller at the rate of F_2=360g N/m

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a=\frac{24\times 1000}{m}

a=\frac{24000}{400}

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using v^2-u^2=2 as

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7 0
4 years ago
Two point charges are brought closer together, increasing the force between them by a factor of 20. By what factor was their sep
olga55 [171]

The separation between them is \frac{r}{\sqrt{20} }

Concept :

If the force increases, distance between charges must decrease. Force is indirectly proportional to the distance squared.

Given,

Two point charges are brought closer together, increasing the force between them by a factor of 20.

Original force is

F = \frac{kq_{1} q_{2} }{r^{2} } -------- ( 1 )

Here, q_{1} , q_{2} are charges and r is the distance between them

New force F' = \frac{kq_{1q_{2} } }{r'^{2} } ----------- (2 )

Divide ( 1 ) and ( 2 )

\frac{F'}{F} = \frac{\frac{kq_{1}q_{2}  }{r'^{2} } }{\frac{kq_{1}_{2}  }{r^{2} } }

20 = \frac{r^{2} }{r'^{2} }

r' = \frac{r}{\sqrt{20} }

Given that force between them are increasing and therefore distance between them decrease by \frac{r}{\sqrt{20} }

Learn more about two point charges here : brainly.com/question/24206363

#SPJ4

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2 years ago
Where would you most likely find an electrostatic precipitator being used?
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In paint industry ..and also in steel industry
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