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IRINA_888 [86]
3 years ago
5

State ohm’s law Q.34.7

Physics
1 answer:
defon3 years ago
4 0

Ohm's law states that: V=RI

Explanation:

Ohm's law states that in a conductor, the potential difference across the conductor is directly proportional to the current flowing through it. Mathematically,

V \propto I

where

V is the potential difference

I is the current

The constant of proportionality is called resistance (R), and it gives a measure of "how much the conductor opposes" to the flow of current. Therefore Ohm's law can be rewritten as

V=RI

where R is the resistance. By rewriting the equation as

I=\frac{V}{R}

we see that the larger the resistance, the lower the current in the conductor.

Learn more about Ohm's law:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

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A hot air balloon has just lifted off and is rising at the constant rate of 1.60 m/s. suddenly, one of the passengers realizes s
Wewaii [24]

speed of balloon which is rising upwards with constant speed is

v_1 = 1.6 m/s

speed of the camera which is thrown up from the ground

v_2 = 10.2 m/s

the distance between camera and balloon when it is thrown from the ground

d = 2.60 m

now let say after time "t" the camera is catch by her friend in the balloon

So the position of balloon and camera must be same

y_{balloon} = y_{camera}

2.6 + 1.60 t = 10.2* t + \frac{1}{2}(-g)t^2

2.6 = 8.6 *t - 4.9 t^2

Solving above quadratic equation we got

t = 0.39 seconds

So after t = 0.39 s her friend will get her camera on the balloon.

5 0
3 years ago
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A light ray is incident on a smooth surface at an angle of 25 degrees with the surface. What is the angle of incidence?
kompoz [17]

The angle will have 45 degree ments

6 0
1 year ago
When you normally drive the freeway between Sacramento and San Francisco at an average speed of 115 km/hr (71 mi/h ), the trip t
erik [133]

Answer:

It takes 20 minutes and 24 seconds more on Friday than that of normal days.

Explanation:

Given:

Average speed on normal days (s₁) = 115 km/h = 71 mi/h

Time taken on normal days (t₁) = 1 hr and 13 min

Average speed on Friday (s₂) = 90 km/h = 56 mi/h

Time taken on Friday (t₂) = ?

Distance covered is same in both case.

Converting time from minutes to hours using the conversion factor, we have:

1 min = \frac{1}{60} hour

∴ 13 min = \frac{13}{60}=0.22\ h

So, t_1=1\ h+0.22\ h=1.22\ h

Using the distance formula for both the days, we get:

d=speed\times time\\\\d=s_1t_1\\d=s_2t_2

Therefore,

s_1t_1=s_2t_2\\\\115\ km/h\times 1.22\ h=90\ km/h\times t_2\\\\t_2=\frac{140.3\ km}{90\ km/h}\\\\t_2=1.56\ hrs

So, time taken on Friday is 1.56 hours.

Time taken on Friday is more and the difference is given as:

Time difference = Time taken on Friday - Time on normal days

Time difference = 1.56 - 1.22 = 0.34 hours

Converting time from hours to minutes using the conversion factor, we have:

1 hour = 60 min

∴ 0.34 hours = 0.34 × 60

                      = 20.4

                      = 20 mins + 0.4 mins

                      = 20 min + (0.4 × 60) = 20 mins + 24 s

So, it takes 20 min and 24 seconds more on Friday than that of normal days.

4 0
3 years ago
During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive
olganol [36]

Answer:

The force is     F_c  =  789.03 \  N    

Explanation:

From the question we are told that

   The tangential  resistive force is F_t  =   115 \ N

   The mass of the wheel is  m  = 1.80 kg

  The diameter of the wheel is  d =  50.0 cm  = 0.5 \ m

   The diameter of the sprocket is  d_c  =  8.50 \ cm =0.085 \ m

  The angular acceleration considered is  \alpha  =  4.30\ rad/s^2

Generally the radius of the wheel is

       r = \frac{d}{2}

=>     r = \frac{0.5}{2}

=>     r = 0.25 \ m

Generally the radius of the sprocket is

       r_c = \frac{d_c}{2}

=>     r_c = \frac{0.085}{2}

=>     r_c = 0.0425 \ m

Generally the moment of inertia of the wheel is mathematically represented as

      I  =  m  *  r^2

=>    I  =  1.80  *  0.25^2

=>    I  = 1.1125 \ kg \cdot m^2

Generally the torque experienced by the wheel due to the forces acting on it  is mathematically represented as

      \tau =  F_c *  r_c  -  F_t  * r

Here  F_c is the force acting on the sprocket

So  

      \tau =  F_c *  0.0425 - 115  * 0.25

       \tau = 0.0425F_c  -  28.75

Generally the torques that will cause the wheel to move with \alpha  =  4.30\ rad/s^2 is mathematically represented as

       \tau  =  I  * \alpha

So

        0.0425F_c  -  28.75  =   I  * \alpha

        0.0425F_c  -  28.75  =   1.1125  *4.30    

       0.0425F_c  -  28.75  =   1.1125  *4.30    

        F_c  =  789.03 \  N    

5 0
3 years ago
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3 years ago
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