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3 years ago

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The speed of light in a material is found to be 2.07 x 108 m/s. What is the most likely material from the options below if the s

peed of light in a vacuum is 3.00 x 108 m/s?

2 answers:

Paraphin [41]3 years ago

4 0

Answer:

1.3636

Explanation:

Write the expression for the refractive index.

n=c/v

c= speed of light in air

v= speed of light in material

=(3×10^8 m/s)/(2.2×10^8 m/s)

=1.3636

Marta_Voda [28]3 years ago

3 0

Answer:

The material is silica quartz.

Explanation:

Given that,

Speed of light in material $v=2.07\times10^{8}\ m/s$

Speed of light in vacuum $c=3.00\times10^{8}\ m/s$

We need to calculate the refractive index

Using formula of refractive index

$n=\dfrac{c}{v}$

Where, c = Speed of light in vacuum

v=Speed of light in material

Put the value into the formula

$n=\dfrac{3.00\times10^{8}}{2.07\times10^{8}}$

$n=1.44$

We know that,

Refractive index of silica quartz is between 1.40 to 1.55

So, This is the refractive index of silica quartz.

Hence, The material is silica quartz.

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a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, fin

trapecia [35]

Answer:

a) $E_{p} = 0$

$E_{k} = 168.7 J$

$E_{m} = 168.7 J$

b) $E_{p} = 73.6 J$

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We have:

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v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

$E_{p} = mgh = 0$

The kinetic energy is:

$E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J$

And the mechanical energies:

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The potential energy is:

$E_{p} = mgh = 1.5*9.81*5 = 73.6 J$

Now, to find the kinetic energy we need to calculate the speed at 5 m:

$v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9$

$v_{f} = \sqrt{126.9} = 11.3 m/s$

$E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J$

And the mechanical energies:

$E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J$

c) At its maximum height:

$v_{f}$ : is the final speed = 0

$h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m$

Now, the potential, kinetic and mechanical energies are:

$E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J$

$E_{k} = \frac{1}{2}mv^{2} = 0$

$E_{m} = 169.2 J + 0 = 169.2 J$

I hope it helps you!

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