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MAVERICK [17]
3 years ago
14

A box weighs 2000N and is accelerated uniformly over a horizontal surface at a rate of 8 m/s^2. The opposing force of friction b

etween the box and the surface is 27.4.
How much force would be required to lift the box upward with an acceleration of 8 m/s^2?
Physics
1 answer:
Naya [18.7K]3 years ago
8 0

Answer:

3633 N

Explanation:

When the box is lift upward, there are only two forces acting on it:

- The force of push, F, upward

- The force of gravity, downward, which is the weight of the object:

W = 2000 N

So, the equation of motion for the box is

F-W = ma

where

m is the mass of the object

a is its acceleration

The mass can be found from the weight of the box:

m=\frac{W}{g}=\frac{2000}{9.8}=204.1 kg

Where g = 9.8 m/s^2 is the acceleration of gravity, and the acceleration is

a=8 m/s^2

So, we can solve for F, the force required:

F=mg+ma=m(g+a)=(204.1)(9.8+8)=3633 N

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Answer:

a) Vx = 1088m/s

b) Vy = -162.93m/s

c) 5246745J

Explanation:

Mass of unbroken body = 23kg

Its velocity along +ve X-axis = 130m/s

Mass of first broken body, m1= 9.4kg

Its velocity along +ve X-axis = 130m/s

Nass of 2nd broken body, m2 = 6.1kg

Its velocity long-lived X - axis = -550m/s

Mass of 3rd broken body = ?

m3 = (23 - 9.4 - 6.1)kg

m3 = 7.5kg

Let velocity along the x-axis = Vx

Let the velocity along the x-axis = Vy

Applying law of conservation of momentum along x-axis

a) m1×0 + m2×(-550) + m3×(Vx) =M × 130

9.4 × 0 + 6.1× (-550) + 7.5(Vx) = 23 ×130

0 + (-5170) + 7.5Vx = 2990

2990 + 5170 = 7.5Vx

8160 = 7.5Vx

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Vx = 1088m/s

b) Aplying conservation of momentum along the x-axis

(m1×130) + (m2 × 0) + (m3× Vy) = 0

(9.4 × 130) + (6.1 ×550) + 7.5Vy = 0

1222 + 0 + 7.5Vy = 0

1222 = -7.5Vy

Vy = 1222/(-7.5)

Vy = -262.93m/s

c) The energy released or change in KE is given by:

1/2[(m1v1^2) + (m2v2^2) +(m3Vx^2) ]= MV^2

Change in KE = 1/2[ 9.4× 130^2 + 6.1 × 550^2 + 7.5 × 1088^2 ] - 1/2(23 × 130^2)

Change in KE = 1/2[158860 + 1845250 + 8878080] - 1/2[388700]

Change in KE = 5441095 - 194350

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