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madreJ [45]
3 years ago
15

Explain why static charges do not build up on a conductor

Physics
2 answers:
MrRissso [65]3 years ago
8 0
Static charge builds on anon moving object so the charges in a conductor are moving so it cannot build up
satela [25.4K]3 years ago
3 0
Because it is conducted away IF the conductor is connected to earth;otherwise as the first feller said it will remain where it is and act as in a capacitor.Example is in the gold leaf electroscope where two gold pieces of gold leaf with the same charge visibly separate from one another;but if the electroscope is earthed the charges disappear and the leaves fall back into contact.As to hospital operating theatres such a spray of fine droplets would be attracted to surfaces especially if they were 
<span>charged and would kill germs in unreachable places.A bit like electrostatic painting of car bodies during manufacture where the paint drops ae electrostatic-ally drawn to all surfaces of a car body which is at high voltage of electrostatic charge.  hope that helped</span>
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A 23.9 g sample of iridium is heated to 89.7 oC, and then dropped into 20.0 g of water in a coffee-cup calorimeter. The temperat
Nikolay [14]

Answer:

The specific heat capacity of iridium = 0.130 J/g°C

Explanation:

Assuming no heat losses to the environment and to the calorimeter,

Heat lost by the iridium sample = Heat gained by water

Heat lost by the iridium sample = mC ΔT

m = mass of iridium = 23.9 g

C = specific heat capacity of the iridium = ?

ΔT = change in temperature of the iridium = 89.7 - 22.6 = 67.1°C

Heat lost by the iridium sample = (23.9)(C)(67.1) = (1603.69 C) J

Heat gained by water = mC ΔT

m = mass of water = 20.0 g

C = 4.18 J/g°C

ΔT = 22.6 - 20.1 = 2.5°C

Heat gained by water = 20 × 4.18 × 2.5 = 209 J

Heat lost by the iridium sample = Heat gained by water

1603.69C = 209

C = (209/1603.69) = 0.130 J/g°C

7 0
3 years ago
Read 2 more answers
A graduated cylinder contains water to the 15-cm'level. A stone was placed in the
qaws [65]

Answer:

The anwser is 6

Explanation:

You subtract the 21-15

6 0
3 years ago
If the net force acting on a stationary object is zero then the object will
Drupady [299]
If the net force is zero, then there is no acceleration, which means no change in velocity. The velocity starts at zero, so it must remain at zero. Therefore, the object will not move.
7 0
3 years ago
You are pedaling forward on your bike. which of the following would decrease your acceleration?
Minchanka [31]

B. An increase in your mass

Because acceleration is inversely proportional to the mass of the object.

a∝ \frac{1}{m}

7 0
3 years ago
An electric range has a constant current of 10 A entering the positive voltage terminal with a voltage of 110 V. The range is op
Gnoma [55]

Answer:

A. 72000 C

B. 1100 W

C. 26.4 cents.

Explanation:

From the question given above, the following data were obtained:

Current (I) = 10 A

Voltage (V) = 110 V

Time (t) = 2 h

A. Determination of the charge.

We'll begin by converting 2 h to seconds. This can be obtained as follow:

1 h = 3600 s

Therefore,

2 h = 2 h × 3600 s / 1 h

2 h = 7200 s

Thus, 2 h is equivalent to 7200 s.

Finally, we shall determine the charge. This can be obtained as follow:

Current (I) = 10 A

Time (t) = 7200 s

Charge (Q) =?

Q = It

Q = 10 × 7200

Q = 72000 C

B. Determination of the power.

Current (I) = 10 A

Voltage (V) = 110 V

Power (P) =?

P = IV

P = 10 × 110

P = 1100 W

C. Determination of the cost of operation.

We'll begin by converting 1100 W to KW. This can be obtained as follow:

1000 W = 1 KW

Therefore,

1100 W = 1100 W × 1 KW / 1000 W

1100 W = 1.1 KW

Thus, 1100 W is equivalent to 1.1 KW

Next, we shall determine the energy consumption of the range. This can be obtained as follow:

Power (P) = 1.1 KW

Time (t) = 2 h

Energy (E) =?

E = Pt

E = 1.1 × 2

E = 2.2 KWh

Finally, we shall determine the cost of operation. This can be obtained as follow:

1 KWh cost 12 cents.

Therefore, 2.2 KWh will cost = 2.2 × 12

= 26.4 cents.

Thus, the cost of operating the range for 2 h is 26.4 cents.

6 0
3 years ago
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