Answer: die
Explanation: oyxagan all goon bc of all dat suffs
Answer:
F = 0.1575 N
Explanation:
When the third sphere touches the first sphere, the charge is distributed between both spheres, then now the first sphere has only half of his original charge.
In this moment then
Sphere one has a charge = Q/2
Sphere three has a charge = Q/2
Now when the third sphere touches the second sphere again the charge is distributed in a manner that both sphere has the same charge.
How the total charge is Q = Q/2 + Q = 3/2Q, when the spheres are separated each one has 3/4Q
Sphere two has a charge = 3/4Q
Sphere three has a charge = 3/4Q
The electrostatic force that acts on sphere 2 due to sphere 1 is:
F = 
F= 
how 
= 0.42
Then
F = 
F = 0.1575 N
Answer:
-589.05 J
Explanation:
Using work-kinetic energy theorem, the work done by friction = kinetic energy change of the base runner
So, W = ΔK
W = 1/2m(v₁² - v₀²) where m = mass of base runner = 72.9 kg, v₀ = initial speed of base runner = 4.02 m/s and v₁ = final speed of base runner = 0 m/s(since he stops as he reaches home base)
So, substituting the values of the variables into the equation, we have
W = 1/2m(v₁² - v₀²)
W = 1/2 × 72.9 kg((0 m/s)² - (4.02 m/s)²)
W = 1/2 × 72.9 kg(0 m²/s² - 16.1604 m²/s²)
W = 1/2 × 72.9 kg(-16.1604 m²/s²)
W = 1/2 × (-1178.09316 kgm²/s²)
W = -589.04658 kgm²/s²
W = -589.047 J
W ≅ -589.05 J
Answer:
55000 W/m²
Explanation:
Parameters given:
Surface temperature, T = 1000°C
Hear transfer coefficient, h = 55 W/m²C
Convection heat transfer coefficient is given as:
h = Heat flux/Temperature
Hence, Heat Flux, q, is given as:
q = h * T
q = 55 * 1000 = 55000 W/m²C
<h2>Answer</h2>
The force will be doubled.
<h2>Explanation</h2>
Using Newton Law II,
<h3>F = ma </h3>
So it can be seen in the formula that force is directly proportional to mass and acceleration.
if mass is doubled ---> force will be doubled, keeping acceleration constant.
Similarly,
if acceleration is doubled ---? force is will be doubled, keeping mass constant.
<em>It is assumed that there is no friction, the object is in the air with no air resistance.</em>
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