Answer:
•2 kilometres.................
Answer ;
<em>Note : Satellite completes one orbit in the same time the earth rotates one about its axis</em>
circumference of the orbit = 2 ×π × 4.23×10⁷ (similar to the earth orbital speed
The time of earth/orbit traveled = 23.93 hrs ,
Speed of the orbit = (distance) ÷ (time)
= circumference ÷ time
= (2 ×π × 4.23×10⁷) ÷ 23.93 (1 hr = 3600 sec.)
= 3085.14 m/s
<em>The orbital velocity is 3085.14 m/s</em>
Answer: The air is compressed after the sound wave passes. 4. The density of air increases and then decreases as the sound wave passes.
Explanation:
Answer:
2.7 J
Explanation:
From the question,
The Net work done by the crate = Work done by the crate in moving if through a distance- work done against friction.
W = Fd-F'd.................... Equation 1
Where F = force applied to the crate, d = distance moved by the crate, F' = force of friction
Given: F = 2.4 N, F' = 0.6 N, d = 1.5 m
Substitute these values into equation 1
W = 2.4(1.5)-0.6(1.5)
W = 3.6-0.9
W = 2.7 J
Answer:
You would use a bar graph