All categories

3 years ago

Find the missing factor 7s^2+19s+10 = (s+2) ()

Mathematics

2 answers:

swat323 years ago

8 0

The missing factor is (7s+5) since 7s * s is 7s^2 and 5*2= 10

Lisa [10]3 years ago

4 0

To find the missing factor, divide 7s^2 + 19s + 10 by s+2. I prefer to do this using synthetic division:
______________
-2 / 7 19 10
-14 -10
----------------------------
7 5 0

Because theres a zero remainder, -2 is a root of the given equation, and (x+2) is a factor. From the coefficients 7 5 we know that the other factor is (7x+5) (answer)
Check this by mult. (7s+5) and (s+2) together. You must get 7s^2+19s+10.

You might be interested in

Find the value of x 12 36 18 24 27 36 0 11 9 0 10 012

vazorg [7]

Answer:

Step-by-step explanation:

I think if I am wrong I am sorry

7 0

3 years ago

What does the c represent in f(x)= ax^2+bx+c

julsineya [31]

In that statement of a function, 'a', 'b', and 'c' all represent
plain old ordinary constant numbers.

4 0

3 years ago

Read 2 more answers

Take my points since im quitting

ValentinkaMS [17]

Answer:

thanks:)

Step-by-step explanation:

hehe

5 0

3 years ago

Read 2 more answers

A cell phone plan costs $20 a month and includes 200 free minutes. Each additional minute costs 5 cents. Assume that you use you

Korolek [52]

Answer:

The total cost C = $10 + $0.05·x

Step-by-step explanation:

The given parameters are

The cost of the cell phone plan per month = $20

The number of minutes of free calls that one can make in a month = 200 minutes

The cost of additional minutes of cell phone call = 5 cent

5 cents to a dollar = $0.05

The total number of minutes of calls made in a month = x

The time duration of a person's usage of the cell phone in a month > 200 minutes

The total cost C of a person's usage per month is given by;

C = $20 + $0.05 × (x - 200) = $20 + 0.05·x - $10

C = $10 + $0.05·x

Where x > 200.

5 0

4 years ago

Tan inverse X + tan inverse Y + tan inverse z=pie prove that X+Y+Z=xyz

vfiekz [6]

Answer:

see explanation

Step-by-step explanation:

Given

$tan^{-1}$ x + $tan^{-1}$ y + $tan^{-1}$ z = π

let

$tan^{-1}$ x = A , $tan^{-1}$ y = B , $tan^{-1}$ z = C , so

x = tanA, y = tanB , z = tanC

Substituting values

A + B + C = π ( subtract C from both sides )

A + B = π - C ( take tan of both sides )

tan(A + B) = tan(π - C) = - tanC ( expand left side using addition identity for tan )

$\frac{tanA+tanB}{1-tanAtanB}$ = - tanC ( multiply both sides by 1 - tanAtanB )

tanA + tanB = - tanC( 1 - tanAtanB) ← distribute

tanA+ tanB = - tanC + tanAtanBtanC ( add tanC to both sides )

tanA + tanB + tanC = tanAtanBtanC , that is

x + y + z = xyz

3 0

3 years ago