Answer:
Yes and im usually sooooo happy to see it.
Answer:
a. changes with temperature.
Explanation:
Hello there!
In this case, according to the thermodynamic definition of the equilibrium constant in terms of the Gibbs free energy of reaction and the temperature of the system:

It is possible to figure out that the equilibrium constant varies as temperature does, not only on the aforementioned definition, but also in the Gibbs free energy as it is also temperature-dependent. Therefore, the appropriate answer is a. changes with temperature.
Best regards!
Answer:
The correct option is B
Explanation:
The reaction is given as

The equilibrium constant for this reaction is mathematically represented as
![K_c = \frac{[concentration \ of \ product ]}{concentration \ of \ reactant } = \frac{[fructose \ 6 -phosphate]}{[Glucose \ 6 - phosphate]}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cfrac%7B%5Bconcentration%20%5C%20of%20%20%5C%20product%20%5D%7D%7Bconcentration%20%5C%20of%20%20%5C%20reactant%20%7D%20%3D%20%5Cfrac%7B%5Bfructose%20%5C%206%20-phosphate%5D%7D%7B%5BGlucose%20%5C%206%20-%20phosphate%5D%7D)
From the question we are told that
[Glucose 6-phosphate] = 2 × [fructose 6-phosphate]
So
![K_c = \frac{[fructose \ 6 -phosphate]}{[2 (fructose \ 6 -phosphate)]} = 0.5](https://tex.z-dn.net/?f=K_c%20%20%3D%20%5Cfrac%7B%5Bfructose%20%5C%206%20-phosphate%5D%7D%7B%5B2%20%28fructose%20%5C%206%20-phosphate%29%5D%7D%20%3D%200.5)
Generally change in free energy
is mathematically represented as

Given that T = 298 K
R = 8.315 J/mol·K



Descriptive investigations are mainly questions to uncover information. it does not have an hypothesis. It is mainly gathering information, it is not repeatable as you are just asking questions