c. 1.5 moles of Cu will contain a total of 9.0 * 10 ^ 23 atoms.
Explanation:
To convert moles into atoms, the molar amount and number of atom is multiplied by Avagadro's number.
Avagadro's number is 6.022×
So applying the formula in the given sample:
A) 0.5×6.022×
3.01× atoms.
B) 0.75 mole of H20
O.75×6.022×
= 4.5166× atoms.
C) 1.5 moles of Cu
1.5×6.022×
= 9.033×
D). 1.5 moles of H2
1.5 × 2 × 6.022 ×
= 18.066 × atoms because H2 is 2 moles of hydrogen.
Atom is the smallest entity of matter having property of the element to which it is a part.
Preparing 15 mg/gl working standard solution from a 20 mg/dl stock solution will require the application of the dilution principle.
Recalling the principle:
initial volume x initial molarity = final volume x final molarity
Since we were not given any volume to work with, we can as well just take an arbitrary volume to be prepared. Let's assume that the stock solution is 10 mL and we want to prepare 15 mg/gl from it:
Applying the dilution principle:
10 x 20 = final volume x 15
final volume = 200/15
= 13.33 mL
This means that in order to prepare 13.33 mL, 15 mg/l working standard solution from 10 ml, 20 mg/dl stock solution, 3.33 mL of the diluent must be added to the stock solution.
More on dilution principle can be found here: brainly.com/question/11493179
Answer:
dS= 1.79*169.504
j/k = 303.41 j/k
Explanation:
Fe3O4(s) + 4H2(g) --> 3Fe (s)+ 4H2O(g)
dS(Fe3O4) =146.4 j/k
dS(H2) =130.684
dS(Fe) =27.78
dS(H2O) =188.825
dSrxn = dS[product]-dS[reactants]
= 3*dS(Fe)+ 4*dS(H2O)-[1*dS(Fe3O4)+ 4dS(H2)]
= [3*27.78 +4*188.825-146.4 -4*130.684] j/k = 169.504 j/k
This is the dS for 1mole Fe3O4
for 1.79 mols Fe3O4
dS= 1.79*169.504 j/k = 303.41 j/k
Hello there.
<span>The rate of evaporation is affected by all of the following except
Answer: </span><span>B. the humidity.
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