Answer with Explanation:
i) Boundary layer thickness: It is the thickness of the boundary layer formed around an object that is placed in the path of a flowing viscous fluid.The boundary layer thickness is the thickness up to which the effect of the object on the flow can be felt. When a viscous flowing fluid encounters an object in it's path of flow, the flowing fluid forms a thin layer of fluid over the object and this layer of fluid is known as boundary layer. This is a phenomenon only observed in the viscous fluids. As shown in the below figure a uniform flow of a viscous fluid encounters a plate, as we can see the thickness of the boundary layer goes on increasing as we move away from the leading edge of the plate the thickness of the boundary layer at any position is termed as boundary layer thickness.
ii) Boundary layer transition: It is the transition of the flow from a laminar nature to fully developed turbulent flow as it moves over an object. It occurs due to change in the Reynolds number of the flow as the effect of boundary layer increases as we move away from the leading edge of the object.
Answer:
Tech A is correct
Explanation:
Tech A is right as its V- angle is identified by splitting the No by 720 °. Of the piston at the edge of the piston.
Tech B is incorrect, as the V-Angle will be 720/10 = 72 for the V-10 motor, and he says 60 °.
Answer:
-0.89%
Explanation:
Assuming a proportional relationship between EMF and Celsius temperature, the measured value of EMF at 100 °C will be interpreted as a temperature of ...
T/5.268 = 400/21.846
T = 5.268(400/21.846) ≈ 96.457 . . . . °C
The error as a fraction of full scale is ...
(96.457 -100)/400 × 100% ≈ -0.886%
The error at 100 °C is about -0.89% of full scale.
Answer:
Required power input = 0.77hp
Explanation:
We need to first of all find the cooling load of the ice machine.
The cooling load is expressed as
=(28 lbm/h) * (169 Btu/lbm)
= 4732 Btu/h.
Therefore, to find the power input of the ice machine, we use:
Wm = Ql / COP
Wm = (4732Btu / 2.2)
Wm = 1971.66 Btu/h
Since we are asked to find power, let's convert to hp.
Therefore
Wm = (1971.66 Btu/m) * (1hp/(2545Btu/m)) = 0.7741hp
The required power input for an ice production rate of 28 lbm/h is 0.77hp