Answer:
Enthalpy at outlet=284.44 KJ
Explanation:
We need to Find enthalpy of outlet.
Lets take the outlet mass m and outlet enthalpy h.
So from mass conservation
m=1+1.5+2 Kg/s
m=4.5 Kg/s
Now from energy conservation
By putting the values
So h=284.44 KJ
Answer:
Explanation:
ADT for an 2-D array:
struct array{
int arr[10];
}arrmain[10];
An application that stores an array with 1000 rows and 1000 columns, where less than 10,000 of the array values are non-zero. The two different implementations for such arrays that would be more space efficient than a standard two-dimensional array implementation requiring one million positions are :
1) struct array{
int *p;
}arr[1000];
2) struct array{
int *p;
}arr[1000];
Answer:
thanks thanks thanks thanks
Explanation:
Answer:
Do you mean 4m^3 and 3.0 tones?
Explanation:
solution:
Mass = m = 3.0 tones
- 1 ton = 1,000 kg
= 3.0 × 1,000
= 3,000 kg
volume = v = 4m^3
Required:
Mass density of oil = p = ?
We know that;
The answer is:
750kg / m^3
Answer:
cout<<"''<<user_word<<"' "<<user_number;
Explanation:
The above question was answered using C++ programming language.
The keyword cout represents print and it carries out print operation only.
It prints all variable in front of it.
Assume the values of user_word and user_number to be Charles and 20, respectively.
The output of the above instruction would be
'Charles' 20 just as it is in the sample output in the question.
In java programming language, it is
System.out.print("'"+user_word+"' "+user_number);
In Qbasic, it is
PRINT "'"+user_word+"' "+ user_number
