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diamong [38]
3 years ago
11

The temperature at which all molecular motion stops is known as: a) Absolute temperature b) molecular temperature c) absolute ze

ro d) Molecular zero e) none of these.
Engineering
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:

c) absolute zero

Explanation:

The fourth principle of thermodynamics posed by the Romanian economist Nicholas Georgescu-Roegen, explains the presence of absolute zero is said that at this temperature the internal molecular movement becomes zero making the internal energy (U) zero, absolute zero is equivalent to -273.15C or 0Kelvin

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Elliot wants to show a spherical radius in a technical drawing. Where should he place the symbol “SR” in the drawing?
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I think it’s ( C with a leader line
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3 years ago
Air enters an adiabatic compressor through 0:5m2 opening and exhausts through a 0:2m2 opening. The inlet conditions of air are 2
gladu [14]

Answer:

i) 43.55 kg/s

ii) 40 m/s

iii)  -199.32 KW

Explanation:

To resolve the above question we have to make some assumptions :

  • mass flow  through the system is constant
  • The only interactions that are between the system and the surrounding are work and heat
  • The fluid is uniform

i) first we have to determine the mass flow rate of the air

M = (\frac{P1}{RT1} )A1v1

    = ( \frac{200}{0.287*325} ) 0.5 * V1 ---------- (1) hence  M = 43.55 kg/s

ii) using this relationship : A1V1 = A2V2 hence V1 = (0.2/0.5) * 100 = 40m/s (    inlet velocity )

input this value into equation 1

iii) Next we will determine the power required to run compressor

attached below

power required = -199.32 KW ( this value indicates that there is power supplied )

8 0
3 years ago
PPE is the first level of protecting an employee from hazards on the job site.
gayaneshka [121]

Answer:

The answer is B) False

8 0
3 years ago
A large plate is fabricated from a steel alloy that has a plane strain fracture toughness of 75 MPa (68.25 ksi). If the plate is
wariber [46]

Answer:

Explanation:

From the given information:

Strain fracture toughness K_k= 75 MPa\sqrt{m}

Tensile stress \sigma = 361 MPa

Value of Y = 1.03

Thus, the minimum length of the critical interior surface crack which will result to fracture can be determined by using the formula:

a_c = \dfrac{1}{\pi} ( \dfrac{k_k}{\sigma Y})^2 \\ \\  a_c = \dfrac{1}{\pi} \Big [ \dfrac{75 \times \sqrt{10^3}}{361 \times 1.03 } \Big]^2 \\ \\  a_c = \dfrac{1}{\pi} \Big [ 6.378474693\Big]^2  \\ \\ \mathbf{ a_c = 12.95 \ mm}

7 0
3 years ago
On a summer day in New Orleans, Louisiana, the pressure is 1 atm: the temperature is 32°C; and the relative humidity is 95 perce
FinnZ [79.3K]

Answer:

Δw =7.95 kg/1000m^3

q = 62362.3 kg/1000m^3

Explanation:

To solve this problem we first need to use the psycrometric chart to determine the enthalpy h1, specific volume vi and absolute humidity col by using the given temperature T1 = 32°C and the relative humidity Ф1 = 95%.  

h_1 =  106.5 kJ/kg

v_1 = 0.91 m^3/kg

w_1 = 0.02905

We will also need the enthalpy h2 and the absolute humidity w_2 at the exit point. We will again use the pyscrometric chart and the given temperature T_2 = 24°C. From the problem we also know that the exit relative humidity is = 60%.  

h2 = 52.6 kJ/kg

w_2 = 0.01119

We need to express the final results in units per 1000 m^3. To do that we will need the mass m of this volume of air V and to calculate that we will use the given pressure p = 1 atm = 101.3 kPa.  

m = R_a*T_1/V.p

m = 1000*101.3/0.287*305K

m = 1157 kg

Because it is a closed system, the amount of water removed Δw can be calculated as:  

Δw =w_1 - w_2

Δw =0.02905- 0.01119

Δw =0.00687 kg/kg* 1157kg/1000m^3

Δw =7.95 kg/1000m^3

From the energy balance equation we can calculate the specific heat q removed from the air.  

q = h_1 - h_2

q = 106.5 kJ/kg - 52.6 kJ/kg

q = 53.9 kJ/kg * 1157kg/1000m^3

q = 62362.3 kg/1000m^3

3 0
3 years ago
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