Answer:
O.
Explanation:
- The element which is oxidized is the element that losses electrons and its oxidation state be more positive.
- The element which is reduced is the element that gain electrons and its oxidation state be more negative.
<em> O goes from 0 to -2, so, it is the element that is reduced.</em>
Answer:
0.24
Explanation:
We are given that
Rate constant for A=
Rate constant for B,k'=0.0750/s
We have to find the value of equilibrium constant for the reaction
Equilibrium constant, for k=
Using the formula
Hence, the value of the equilibrium constant for the reaction
at this temperature=0.24
The question is incomplete, the complete question is; Describe the preparation of 2.00 L of 0.108 M BaCl2 from BaCl2.2H2O
Answer:
See explanation
Explanation:
First we must know the molar mass of the compound = 244.3 g/mol
Now we must calculate the number of moles of BaCl2.2H2O in the solution.
number of moles = concentration * volume = 0.108 M * 2.00 L = 0.216 moles
Now the mass of solid that we need to take can be obtained from;
number of moles = mass/molar mass
mass = number of moles * molar mass
mass = 0.216 moles * 244.3 g/mol
Mass = 52.8 g
Hence, we must weigh 52.8 g of BaCl2.2H2O accurately in a balance and dissolve it in 2 L of water to give 0.108 M solution of BaCl2.2H2O.
Using the general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
(105*220)/275 = (P₂*95)/310
(105*220)*310/275 = P₂*95
(105*220*310)/(275*95) = P₂
274.11 = P₂
P₂ = 274.11 kPa
New Pressure = 274.11 kPa
<span>the answer is B) <span>sodium and oxygen </span></span>
