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3 years ago

The answer ........................... ..

Chemistry

1 answer:

algol [13]3 years ago

5 0

assuming the question is 2. you add a prefix to the base unit, it shows it right there. Depending on how much larger or smaller the prefix changes from mega-micro.

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Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points from highest to l

muminat

Answer:

NH4Cl > Li2SO4 > CoCl3

Explanation:

Let us recall that the freezing point depression depends on the molality of the solution and the number of particles present.

Let us also recall that freezing point depression is a colligative property. It depends on the number of particles present in solution.

Usually, the more the number of particles present, the lower the freezing point. Hence, NH4Cl which has only two particles will have the highest freezing point while CoCl3 which has four particles will have the lowest freezing point.

4 0

3 years ago

5. A 25 ml graduated cylinder has a volume of water of 10 ml, when a glass marble is place in the

IceJOKER [234]

Answer:

The volume of the marble is 10 mL.

Explanation:

From the question given above, the following data were obtained:

Volume of water = 10 mL

Rise in water = 10 mL

Volume of marble =.?

From the question given above, the water level rise by 10 mL when a glass marble was placed into the water.

This is equally the volume of the marble as the marble will displace it's volume when placed in the water according to Archimedes' principle.

Therefore,

Rise in water = 10 mL = volume of marble.

4 0

3 years ago

Objects are recognized by their 1) shape 2) properties 3) odor 4)color

8_murik_8 [283]

I would say properties.

3 0

3 years ago

A can of coke contains 25 mL of carbon dioxide gas at 100kPa. If you take it on a hike up Mount Everest and the pressure decreas

Mazyrski [523]

Answer:

50 mL

Explanation:

We can solve this problem by using Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

$p\propto \frac{1}{V}$

where

p is the pressure of the gas

V is the volume of the gas

The equation can be rewritten as

$p_1 V_1 = p_2 V_2$

where in this problem:

$p_1 = 100 kPa$ is the initial pressure of the gas in the coke

$V_1=25 mL$ is the initial volume

$p_2=50 kPa$ is the final pressure

Solving for V2, we find the final volume:

$V_2=\frac{p_1 V_1}{p_2}=\frac{(100)(25)}{50}=50 mL$

7 0

3 years ago

can someone help me with these? I just started chemistry this semester, and since it's involving math I don't see myself doing g

V125BC [204]

Any non zero digits are significant. (120 has 2 sig figs)

Zeroes between significant digits are significant. (103 has 3 sig figs)

Zeroes only count if there is a decimal point and if they are following a significant digit. (.600 has 3 sig figs; .067 has 2 sig figs)

1) 1278.50 = 6 sig figs

2) 120000 = 2 sig figs

3) 90027.00 = 7 sig figs

4) 0.0053567 = 5 sig figs

5) 670 = 2 sig figs

6) 0.00730 = 3 sig figs

That's all I'm gonna do so yeah.

Now for the rounding, it's basically rounding but it must have the x amount of sig figs after rounding. It's pretty hard to explain.

19, I'm not really sure. Might be 120 with a decimal point at the end.

20) 5.457, alright so here, since we are rounding to three significant digits, we look at the third sig fig. The third sig fig here would be 5. Then we just round. Since the number next to 5 is 7, we round 5 up to 6.

So 5.457 rounded to 3 sig figs would be 5.46

21) 0.0008769, the third sig fig here would be 6. You round 6 up to 7 because the number next to it is 9.

So 0.0008769 rounded to 3 sig figs would be 0.000877

So I hope you get it, I'm gonna let you do the rest.

4 0

2 years ago