I would say all of the above
Equation is:
Ca(NO3)2 + Na3PO4 —> NaNO3 + Ca3(PO4)2
Balance it out
3Ca(NO3)2 + 2Na3PO4 —> 6NaNO3 + Ca3(PO4)2
You have 96.1g of Calcium Nitrate
Moles = Mass/Molar Mass
Molar mass of Calcium Nitrate is 164.088 g/mol
96.1g / 164.088 g/mol =0.586 moles
Mole ratio is 3:1
Therefore 0.586/3 moles of calcium phosphate
Moles x molar mass = mass
0.586/3 x 310.18 g/mol = 60.6~g roughly as theoretical yield
Answer:
Explanation:
In this problem, we need to convert 
to miles per hour
We know that,
1 mile = 1.609 km
1 hour = 3600 seconds
Hence,
Answer:
The concentration would be 0.76 mol/L.
The most common way to solve this problem is to use the formula
c1V1=c2V2
In your problem,
c1 = 4.2 mol/L; V1 = 45.0 mL
c2 = ?; V2 = 250 mL
c2=c1×V1V2 = 4.2 mol/L × 45.0mL250mL = 0.76 mol/L
This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).
Explanation:
if it is helpful...... plzz like and follow
C3H6Br2 2 isomers:- bominated allkane
CH3CH2CHBr2 1,1-dibromopropane
<span>CH3CHBrCH2Br 1,2-dibromopropane
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