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8_murik_8 [283]

3 years ago

11

if there is 27 marbles in a bag and the amount of red marbles is 5 less than 3 times the amount of blue marbles how many marbles

are blue and how many are red

1 answer:

Hatshy [7]3 years ago

3 0

19 red marbles and 8 blue marbles

Hope this helps ;)

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What is the sum of all the positive integers from <br> √<br> 24<br> to <br> √<br> 102<br> ?

Eva8 [605]

Answer:

The sum of all positive integers is

5 + 6 + 7 + 8 + 9 + 10

= <em>45</em>

Step-by-step explanation:

Because $\sqrt{24} = 4.89$ and $\sqrt{102} = 10.09$

So positive numbers between 4.9 and 10.09 are

<em>5+6+7+8+9+10 = 45</em>

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2 years ago

The point (12, 5) is on the terminal side of angle θ.

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Tanα=5/12

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3 years ago

a distributor wants to make 1000 pounds of trail mix that is 8% raisins. He will use a mix that is 5% raisins and a mix that is

leva [86]

Answer:

200 pounds 20% raisins

800 pounds 5% raisins

Step-by-step explanation:

Let number of 5% be x

and number of 20% be y

x + y = 1000

Also;

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3 years ago

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An antique collectible has a value of $235 right now. It will increase in value by 9% each year. Find the value the collectible

kirill [66]

Answer:

Step-by-step explanation: An antique collectible has a value of $235 right now. It will increase in value by 9% each year. Find the value the collectible after 16 years, A.$2115 B. $1017 C.$856 D.933

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2 years ago

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Make n the subject of the formula

kogti [31]

Answer:

$\mathsf{ \frac{m + 21}{5} = n }$

Step-by-step explanation:

To make "n" the subject of the formula, rearrange the formula so it begins with " n = "

To isolate the variable "n", you need to inverse the other terms on that side of the equation where "n" really is.

=> m = 5n - 21

<em>there's</em><em> </em><em>a</em><em> </em><em>"</em><em>-21</em><em>"</em><em> </em><em>next</em><em> </em><em>to</em><em> </em><em>"</em><em>5n</em><em>"</em><em>,</em><em> </em><em>inverse</em><em> </em><em>of</em><em> </em><em>subtraction</em><em> </em><em>is</em><em> </em><em>addition</em><em>,</em><em> </em><em>so</em><em> </em><em>add</em><em> </em><em>21</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>.</em><em> </em>

=> m + 21 = 5n <u>-</u> <u>21</u> + <u>21</u>

=> m+ 21 = 5n

<em>There's</em><em> </em><em>also</em><em> </em><em>a</em><em> </em><em>5</em><em> </em><em>attached</em><em> </em><em>to</em><em> </em><em>n</em><em>,</em><em> </em><em>that</em><em> </em><em>means</em><em> </em><em>the</em><em> </em><em>multiplication</em><em> </em><em>of</em><em> </em><em>n</em><em> </em><em>with</em><em> </em><em>5</em><em>,</em><em> </em><em>the</em><em> </em><em>inverse</em><em> </em><em>of</em><em> </em><em>multiplication</em><em> </em><em>is</em><em> </em><em>division</em><em>,</em><em> </em><em>so</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em> </em><em>by</em><em> </em><em>5</em>

<em> $\mathsf{ \frac{m + 21}{5} = n }$ </em>

3 0

3 years ago