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Lapatulllka [165]
4 years ago
11

Properties of metals

Chemistry
1 answer:
Nitella [24]4 years ago
3 0

Answer:

Physical Properties of Metals :

Metals are lustrous, malleable, ductile, good conductors of heat and electricity. Other properties include: State: Metals are solids at room temperature with the exception of mercury, which is liquid at room temperature (Gallium is liquid on hot days).

Hope this helps! :D

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Why did Rutherford say that bombarding atoms with particles was like “playing with marbles”?
s2008m [1.1K]

In 1917, Rutherford discovered something new, he bombarded alpha particles on nitrogen gas and noticed that occasionally an oxygen atom is produced. From this he concluded that the alpha particles removes proton from the nucleus (positively charged particle). He named this playing with marbles and he become the first one to split an atom. Thus, by bombarding nitrogen with alpha particles, he observed the production of oxygen, a different element.

Therefore, he said bombarding atoms with particles is similar to playing with marbles.

8 0
3 years ago
Q2. The table gives the composition of three particles.
Kisachek [45]

Answer:

The proton and electrons are equal,

15protons and 15electrons

Explanation:

An atom is the smallest electrical neutral particle of an element so it means that every atom have same number of protons and electrons.

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3 years ago
The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s
raketka [301]

Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

Explanation :

The dissociation of acid reaction is:

                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

K_a=6.3\times 10^{-5}

The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

Thus, the equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

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3 years ago
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<h3><u>Answer</u>;</h3>

Concave Lenses

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