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WINSTONCH [101]
3 years ago
7

The combustion of palmitic acid in a bomb calorimeter yields energy in the form of heat released upon oxidation. From a thermody

namic perspective and with respect to the calorimeter experiment, what would you expect the combustion of the same amount of palmitic acid in our body to yield?a. less energyb. more energyc. the same amount of energyd. The calorimeter experiment is irrelevant to the combustion of palmitic acid in the human body.
Chemistry
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

"The same amount of energy" is the combustion of the same amount of palmitic acid in our body to yield.

Explanation:

A bomb calorimeter is an apparatus used to measure the amount of heat out or fascinated by a chemical reaction. This apparatus is airtight and has thermal insulation, which means that the organization doesn't alteration heat with the environments. So, by the variance of the temperature measured on the system (ΔT), the mass of a solution (m) and the specific heat of water (c) it's likely to compute the heat in a reaction that happens in aqueous solution, by the equation below:

                                           Q = m \times c\times \delta T

The heat, or the energy, of the response doesn't depend on where the response is happening, so the sum of energy measured on the bomb calorimeter will be the same in our body.

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3 years ago
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Information-
tekilochka [14]

Answer:

So first thing to do in these types of problems is write out your chemical reaction and balance it:

Mg + O2 --> MgO

Then you need to start thinking about moles of Magnesium for moles of Magnesium Oxide. Based on the above equation 1 mole of Magnesium is needed to make one mole of Magnesium Oxide.

To get moles of magnesium you need to take the grams you started with (.418) and convert to moles by dividing by molecular weight of Mg (24.305), this gives you .0172 moles of Mg.

The theoretical yield would be the assumption that 100% of the magnesium will be converted into Magnesium Oxide, so you would get, based on the first equation, .0172 mol of MgO. Multiplying this by the molecular weight of MgO (24.305+16) gives us .693 g of MgO.

The percent yield is what you actually got in the experiment, and for this you subtract off the total mass from the crucible mass, or 27.374 - 26.687, which gives .66 g of MgO obtained.

Percent yield is acutal/theoretical, .66/.693, or 95.24%.

I'll let you do the same for the second trial, and average percent yield is just an average of the two trials percent yield.

Hope this helps.

6 0
3 years ago
Atoms share one or more pairs of electrons.<br><br> Options:<br> Ionic Bond or Covalent Bond?
garri49 [273]

Answer:

covalent bonds

Explanation:

ionic transfer of e^- ions formed (charges)

ionic=non-metal+ metal

ex: F+Ca

covalent sharing e^- no true charges

covalent= non-metal+ non-metal

ex: F+P

( my notes)

5 0
2 years ago
What is the molar solubility of agcl in 0. 30 m nacl at 25°C. ksp for agcl is 1. 77 × 10^-10.
Rzqust [24]

Molar solubility of AgCl will be  0.59 ×  10^{-10} M.

The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.

A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.

Calculation of molar solubility:

Given data:

M = 0.30 M

K_{sp} = 1.77 × 10^{-10}

The reaction can be written as:

AgCl ⇔ Ag^{+} + Cl^{-}

s            s         (s+0.30)

K_{sp}  = [Ag^{+} ]+ [Cl^{-}]

1.77 × 10^{-10} = s (0.30)

s = 1.77 × 10^{-10}  / 0.3

s = 0.59 ×  10^{-10} M

Therefore, molar solubility of AgCl will be  0.59 ×  10^{-10} M.

To know more about molar solubility

brainly.com/question/16243859

#SPJ4

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